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Hermite–Lindemann and Gel'fond–Schneider for ℒ_u = ℒ + ℚu + ℚū (u transcendental over the field of ℒ̃, uū algebraic): 0 is its only algebraic element, and l, βl ∈ ℒ_u, l ≠ 0, β ∈ Q̄ force β ∈ ℚ

Proved
DiazModulus.logAlg_adjoin_circle_point_hermite_lindemann_gelfond_schneider

by carlok · Oct 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Here L\mathcal{L}L is the set of logarithms of algebraic numbers (the z∈Cz \in \mathbb{C}z∈C with eze^zez algebraic), and L~\widetilde{\mathcal{L}}L is the Q‾\overline{\mathbb{Q}}Q​-vector space spanned by 111 and L\mathcal{L}L. Let FFF be the subfield of C\mathbb{C}C generated by L~\widetilde{\mathcal{L}}L, that is, by Q‾\overline{\mathbb{Q}}Q​ and L\mathcal{L}L. Let u∈Cu \in \mathbb{C}u∈C be transcendental over FFF, with uuˉu\bar uuuˉ algebraic, and put Lu=spanQ(L)+spanQ(u,uˉ)\mathcal{L}_u = \mathrm{span}_{\mathbb{Q}}(\mathcal{L}) + \mathrm{span}_{\mathbb{Q}}(u, \bar u)Lu​=spanQ​(L)+spanQ​(u,uˉ); as L\mathcal{L}L is a Q\mathbb{Q}Q-vector space, this is L+Qu+Quˉ\mathcal{L} + \mathbb{Q}u + \mathbb{Q}\bar uL+Qu+Quˉ. Then:

  • (Hermite–Lindemann) every algebraic z∈Luz \in \mathcal{L}_uz∈Lu​ is 000;
  • (Gel'fond–Schneider) if l0≠0l_0 \neq 0l0​=0 and βl0\beta l_0βl0​ both lie in Lu\mathcal{L}_uLu​ and β\betaβ is algebraic, then β∈Q\beta \in \mathbb{Q}β∈Q.

Proof. Both clauses are special cases of Baker's theorem for Lu\mathcal{L}_uLu​ (DiazModulus.logAlg_adjoin_circle_point_baker_linear_forms). Hermite–Lindemann is the case n=1n = 1n=1: a non-zero algebraic z∈Luz \in \mathcal{L}_uz∈Lu​ is Q\mathbb{Q}Q-independent on its own, and −z+1⋅z=0-z + 1 \cdot z = 0−z+1⋅z=0 is a vanishing form with algebraic coefficients, not all zero. Gel'fond–Schneider is the case n=2n = 2n=2, b0=0b_0 = 0b0​=0: if β\betaβ is not rational, then (l0,βl0)(l_0, \beta l_0)(l0​,βl0​) is Q\mathbb{Q}Q-independent, since sl0+tβl0=0sl_0 + t\beta l_0 = 0sl0​+tβl0​=0 with t≠0t \neq 0t=0 would make β=−s/t\beta = -s/tβ=−s/t rational, and β⋅l0−1⋅(βl0)=0\beta \cdot l_0 - 1 \cdot (\beta l_0) = 0β⋅l0​−1⋅(βl0​)=0 is again forbidden.

Novelty. With Lu\mathcal{L}_uLu​ in place of L\mathcal{L}L, this is the Hermite–Lindemann theorem together with the Gel'fond–Schneider theorem (1934), both derived here from Baker's theorem for Lu\mathcal{L}_uLu​. Not found in the sources read; routine.

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem logAlg_adjoin_circle_point_hermite_lindemann_gelfond_schneider
    (u : ℂ) (hρ : IsAlgebraic ℚ (u * conj u))
    (hu : Transcendental (Subfield.closure (LogAlgTilde : Set ℂ)) u) :
    (∀ z ∈ (Submodule.span ℚ LogAlg ⊔ Submodule.span ℚ ({u, conj u} : Set ℂ)), IsAlgebraic ℚ z → z = 0) ∧
    (∀ l₀ β : ℂ, l₀ ∈ (Submodule.span ℚ LogAlg ⊔ Submodule.span ℚ ({u, conj u} : Set ℂ)) → β * l₀ ∈ (Submodule.span ℚ LogAlg ⊔ Submodule.span ℚ ({u, conj u} : Set ℂ)) →
      l₀ ≠ 0 → IsAlgebraic ℚ β → ∃ q : ℚ, β = (q : ℂ)) := by
  sorry

end DiazModulus
Source
Restates the Hermite–Lindemann theorem (Ch. Hermite 1873; F. Lindemann 1882) and the Gel'fond–Schneider theorem (A. O. Gel'fond 1934; Th. Schneider 1934) with ℒ replaced by ℒ_u = ℒ + ℚu + ℚū; both are derived from Baker's theorem (A. Baker, Linear forms in the logarithms of algebraic numbers I, Mathematika 13 (1966), 204–216). The ℒ_u form was not found in the sources read. Uses DiazModulus.logAlg_adjoin_circle_point_baker_linear_forms. R19 of the Diaz modulus mission. Formal proof: Diaz modulus mission, 18 October 2026 (C. Perassi).

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