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Theorem D as a barrier: some ℚ-subspace L ⊇ ℒ of ℂ has all the Theorem D properties and contains u ≠ 0 with |u| algebraic

Proved
DiazModulus.theorem_D_barrier

by carlok · Oct 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Here L\mathcal{L}L is the set of logarithms of algebraic numbers (the z∈Cz \in \mathbb{C}z∈C with eze^zez algebraic), and L~\widetilde{\mathcal{L}}L is the Q‾\overline{\mathbb{Q}}Q​-vector space spanned by 111 and L\mathcal{L}L. There is a Q\mathbb{Q}Q-vector subspace LLL of C\mathbb{C}C with L⊆L\mathcal{L} \subseteq LL⊆L such that, with L~=spanQ‾({1}∪L)\widetilde L = \mathrm{span}_{\overline{\mathbb{Q}}}(\{1\} \cup L)L=spanQ​​({1}∪L), LLL has the properties

  • (conjugation) zˉ∈L\bar z \in Lzˉ∈L for every z∈Lz \in Lz∈L;
  • (Baker) if n≥0n \geq 0n≥0, l1,…,ln∈Ll_1, \dots, l_n \in Ll1​,…,ln​∈L are linearly independent over Q\mathbb{Q}Q, and b0,b1,…,bnb_0, b_1, \dots, b_nb0​,b1​,…,bn​ are algebraic numbers, not all zero, then b0+∑i=1nbili≠0b_0 + \sum_{i=1}^{n} b_il_i \neq 0b0​+∑i=1n​bi​li​=0;
  • (Hermite–Lindemann) every algebraic z∈Lz \in Lz∈L is 000;
  • (Gel'fond–Schneider) if l0≠0l_0 \neq 0l0​=0 and βl0\beta l_0βl0​ both lie in LLL and β\betaβ is algebraic, then β∈Q\beta \in \mathbb{Q}β∈Q;
  • (Roy, relative to L~\widetilde{\mathcal{L}}L) if no x1,x2x_1, x_2x1​,x2​, linearly independent over Q‾\overline{\mathbb{Q}}Q​, and y1,y2,y3y_1, y_2, y_3y1​,y2​,y3​, linearly independent over Q‾\overline{\mathbb{Q}}Q​, have all six products xiyjx_iy_jxi​yj​ in L~\widetilde{\mathcal{L}}L, then no such families have all six products in L~\widetilde LL;
  • (six exponentials) no x1,x2∈Cx_1, x_2 \in \mathbb{C}x1​,x2​∈C, linearly independent over Q\mathbb{Q}Q, and y1,y2,y3∈Cy_1, y_2, y_3 \in \mathbb{C}y1​,y2​,y3​∈C, linearly independent over Q\mathbb{Q}Q, have all six products xiyjx_iy_jxi​yj​ in LLL;
  • (four exponentials in transcendence degree one) if ℓ11,ℓ12,ℓ21,ℓ22∈L\ell_{11}, \ell_{12}, \ell_{21}, \ell_{22} \in Lℓ11​,ℓ12​,ℓ21​,ℓ22​∈L are non-zero, ℓ11ℓ22=ℓ12ℓ21\ell_{11}\ell_{22} = \ell_{12}\ell_{21}ℓ11​ℓ22​=ℓ12​ℓ21​, and the Q\mathbb{Q}Q-algebra they generate has transcendence degree at most 111 over Q\mathbb{Q}Q, then there are a,b∈Qa, b \in \mathbb{Q}a,b∈Q, not both zero, with aℓ11+bℓ21=aℓ12+bℓ22=0a\ell_{11} + b\ell_{21} = a\ell_{12} + b\ell_{22} = 0aℓ11​+bℓ21​=aℓ12​+bℓ22​=0 (the rows of the matrix (ℓij)(\ell_{ij})(ℓij​) are linearly dependent over Q\mathbb{Q}Q), or with aℓ11+bℓ12=aℓ21+bℓ22=0a\ell_{11} + b\ell_{12} = a\ell_{21} + b\ell_{22} = 0aℓ11​+bℓ12​=aℓ21​+bℓ22​=0 (its columns are),

and some u∈Lu \in Lu∈L has u≠0u \neq 0u=0 and ∣u∣|u|∣u∣ algebraic.

The Roy clause is an implication: Roy's strong six exponentials theorem for L~\widetilde{\mathcal{L}}L (Roy 1992, Cor. 2) is its hypothesis, not a hypothesis of the node, so the statement is unconditional.

What it means. DiazModulus.span_logAlg_theorem_D_properties shows that L\mathcal{L}L itself has these properties and that Diaz's conjecture says exactly that no non-zero element of L\mathcal{L}L has algebraic modulus, while DiazModulus.theorem_D_barrier gives a Q\mathbb{Q}Q-space L⊇LL \supseteq \mathcal{L}L⊇L with the same properties that does contain such an element. So the listed properties, as axioms about (L,L~)(\mathcal{L}, \widetilde{\mathcal{L}})(L,L) (with Roy's theorem for L~\widetilde{\mathcal{L}}L supplying the hypothesis of the Roy clause), do not prove Diaz's conjecture: an argument from them alone would apply to LLL and its Q‾\overline{\mathbb{Q}}Q​-span with 111 as well. Here a candidate for LLL means a non-zero u∈Lu \in Lu∈L with ∣u∣|u|∣u∣ algebraic; it is not DiazModulus.IsCandidate, which asks for eue^ueu to be algebraic. The barrier is a model-existence statement about membership only: the model has no exponential function, so it says nothing about arguments through the values exiyje^{x_iy_j}exi​yj​, such as Waldschmidt's theorem of 1973, or through Roy's rank bounds for larger matrices.

Proof. DiazModulus.exists_circle_point_transcendental_over_logAlgTilde_closure at ρ=1\rho = 1ρ=1 gives uuu with uuˉ=1u\bar u = 1uuˉ=1 that is transcendental over the field generated by L~\widetilde{\mathcal{L}}L; its hypothesis that uuˉu\bar uuuˉ is algebraic holds since 111 is. Then DiazModulus.logAlg_adjoin_circle_point_theorem_D gives every listed property for L=Lu=spanQ(L)+spanQ(u,uˉ)L = \mathcal{L}_u = \mathrm{span}_{\mathbb{Q}}(\mathcal{L}) + \mathrm{span}_{\mathbb{Q}}(u, \bar u)L=Lu​=spanQ​(L)+spanQ​(u,uˉ), together with L⊆L\mathcal{L} \subseteq LL⊆L, u∈Lu \in Lu∈L, u≠0u \neq 0u=0 and ∣u∣|u|∣u∣ algebraic.

Novelty. Not found in the sources read; routine, given Theorem D (DiazModulus.logAlg_adjoin_circle_point_theorem_D) and the generic circle point (DiazModulus.exists_circle_point_transcendental_over_logAlgTilde_closure).

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem theorem_D_barrier :
    ∃ L : Submodule ℚ ℂ, (∀ z ∈ LogAlg, z ∈ L) ∧
      /- conjugation -/
      (∀ z ∈ L, conj z ∈ L) ∧
      /- (D2) Baker -/
      (∀ (n : ℕ) (l : Fin n → ℂ), (∀ i, l i ∈ L) → LinearIndependent ℚ l →
        ∀ (b₀ : ℂ) (b : Fin n → ℂ), IsAlgebraic ℚ b₀ → (∀ i, IsAlgebraic ℚ (b i)) →
          (b₀ ≠ 0 ∨ ∃ i, b i ≠ 0) → b₀ + ∑ i, b i * l i ≠ 0) ∧
      /- (D2) Hermite-Lindemann -/
      (∀ z ∈ L, IsAlgebraic ℚ z → z = 0) ∧
      /- (D2) Gel'fond-Schneider -/
      (∀ l₀ β : ℂ, l₀ ∈ L → β * l₀ ∈ L → l₀ ≠ 0 → IsAlgebraic ℚ β →
        ∃ q : ℚ, β = (q : ℂ)) ∧
      /- (D3) Roy, relative to ℒ: strong six exponentials for ℒ̃ gives it for span Q̄ (insert 1 L) -/
      ((∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ),
          LinearIndependent (↥Qbar) x → LinearIndependent (↥Qbar) y →
          ¬ (∀ i j, x i * y j ∈ LogAlgTilde)) →
        ∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ),
          LinearIndependent (↥Qbar) x → LinearIndependent (↥Qbar) y →
          ¬ (∀ i j, x i * y j ∈ Submodule.span Qbar (insert 1 (L : Set ℂ)))) ∧
      /- (D3) six exponentials -/
      (∀ (x : Fin 2 → ℂ) (y : Fin 3 → ℂ), LinearIndependent ℚ x → LinearIndependent ℚ y →
        ¬ (∀ i j, x i * y j ∈ L)) ∧
      /- (D4) four exponentials in transcendence degree one -/
      (∀ l₁₁ l₁₂ l₂₁ l₂₂ : ℂ, l₁₁ ∈ L → l₁₂ ∈ L → l₂₁ ∈ L → l₂₂ ∈ L →
        l₁₁ ≠ 0 → l₁₂ ≠ 0 → l₂₁ ≠ 0 → l₂₂ ≠ 0 → l₁₁ * l₂₂ = l₁₂ * l₂₁ →
        Algebra.trdeg ℚ ↥(Algebra.adjoin ℚ ({l₁₁, l₁₂, l₂₁, l₂₂} : Set ℂ)) ≤ 1 →
        (∃ a b : ℚ, ¬(a = 0 ∧ b = 0) ∧ (a : ℂ) * l₁₁ + (b : ℂ) * l₂₁ = 0 ∧ (a : ℂ) * l₁₂ + (b : ℂ) * l₂₂ = 0) ∨
        (∃ a b : ℚ, ¬(a = 0 ∧ b = 0) ∧ (a : ℂ) * l₁₁ + (b : ℂ) * l₁₂ = 0 ∧ (a : ℂ) * l₂₁ + (b : ℂ) * l₂₂ = 0)) ∧
      ∃ u ∈ L, u ≠ 0 ∧ IsAlgebraic ℚ ((‖u‖ : ℝ) : ℂ) := by
  sorry

end DiazModulus
Source
Not found in the sources read. The properties are those of Theorem D (DiazModulus.logAlg_adjoin_circle_point_theorem_D): Baker's theorem (A. Baker, Linear forms in the logarithms of algebraic numbers I, Mathematika 13 (1966), 204–216); Hermite–Lindemann (Ch. Hermite 1873; F. Lindemann 1882); Gel'fond–Schneider (A. O. Gel'fond 1934; Th. Schneider 1934); the six exponentials theorem (S. Lang, Introduction to Transcendental Numbers, Addison-Wesley, 1966, chapter II; K. Ramachandra, Contributions to the theory of transcendental numbers I, II, Acta Arith. 14 (1968)); the four exponentials theorem in transcendence degree one (M. Waldschmidt, Solution du huitième problème de Schneider, J. Number Theory 5 (1973), 191–202; W. D. Brownawell, The algebraic independence of certain numbers related by the exponential function, J. Number Theory 6 (1974), 22–31), and Roy's strong six exponentials theorem (D. Roy, Matrices whose coefficients are linear forms in logarithms, J. Number Theory 41 (1992), 22–47, Cor. 2) as an implication. Uses DiazModulus.exists_circle_point_transcendental_over_logAlgTilde_closure and DiazModulus.logAlg_adjoin_circle_point_theorem_D. R19 of the Diaz modulus mission. Formal proof: Diaz modulus mission, 18 October 2026 (C. Perassi).

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