Rank construction: maps jointly cover on every -set when
ProvedErdos624.rank_covercombinatoricserdos-problems
Theorem. Let , with . Then there are maps such that for every -set ,
The maps depend only on (each point of is assigned a slot and is the point in slot ). In the context of Erdős Problem 624, this shows that a family of maps need have no common omitted point on any -set once , so any common-hole lemma for several maps needs large compared with .
Formalization Note. , maps indexed by .
Preamble
import Mathlib import Definitions.Def_Erdos624_defs open Finset
Formal statement
namespace Erdos624
theorem rank_cover (r n k : ℕ) (hn : 0 < n) (h : n ≤ r * (k + 1)) :
∃ g : Fin r → Finset (Fin n) → Fin n,
∀ Y : Finset (Fin n), #Y = k → ∀ u : Fin n, ∃ i, ∃ A ⊆ Y, g i A = u := by sorry
end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; (B.6)/(B.L3) of claim from GPT 6.1 Sol (fourth answer, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)