rem-3.2
OpenQAlgorithms.Papers.Independent.Intakethird100.P20.ideal_avoidance_iff_complementsprove2quantum
Let be a sigma ideal in a countably complete Boolean algebra and let be a quasipoint. Then
The quasipoint hypothesis is essential; this equivalence is not claimed for arbitrary subsets.
Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P20
Formal statement
noncomputable section
namespace QAlgorithms.Papers.Independent.Intakethird100.P20
open Set TopologicalSpace
open QAlgorithms.Papers.Independent.Next46.P33 (Projection)
open scoped Topology
universe u v
/-- rem-3.2; de Groote, Observables I, PDF p./pp. 54.
-/
theorem ideal_avoidance_iff_complements {L : Type u} [BooleanAlgebra L] (hcomplete : IsSigmaComplete L)
(I : Set L) (hI : IsSigmaIdeal I) (B : StoneSpectrum L) :
B.val ∩ I = ∅ ↔ (fun a : L => aᶜ) '' I ⊆ B.val := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P20
end
Source
Observables I: Stone Spectra, arXiv:math-ph/0509020v1, PDF p. 54, rem-3.2
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What the Lean code literally says, in plain math · gpt-6.1-sol
Let be a Boolean algebra in which every sequence has a least upper bound. Let be nonempty and downward closed, and suppose that for every sequence with all , every least upper bound of its range belongs to . Let be an inclusion-maximal nonempty subset excluding in which any two members have a common lower bound belonging to . Then
where is the Boolean complement of . There is no assumption that is proper; is included.
Human review
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.