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Mixed-state tightness and failure of the support-projector choice

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QAlgorithms.Papers.Independent.Intakethird100.P83.deterministicMixedTightness

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let ρ(1/2)\rho^{(1/2)}ρ(1/2) be the equal mixture of the three normalized qutrit vectors (∣01⟩+∣10⟩)/2(|01\rangle+|10\rangle)/\sqrt2(∣01⟩+∣10⟩)/2​, (∣02⟩+∣20⟩)/2(|02\rangle+|20\rangle)/\sqrt2(∣02⟩+∣20⟩)/2​, and (∣12⟩+∣21⟩)/2(|12\rangle+|21\rangle)/\sqrt2(∣12⟩+∣21⟩)/2​. Let PPP be its support projector. With E1E_1E1​ the one-copy exact positive-real-target PPT rate and EΓ,0E_{\Gamma,0}EΓ,0​ its regularization, one has

E1(ρ(1/2))=EΓ,0(ρ(1/2))=EΓ(ρ(1/2))=EW(ρ(1/2))=log⁡2(3/2)<log⁡2(5/3)=EN(ρ(1/2)).E_1(\rho^{(1/2)})=E_{\Gamma,0}(\rho^{(1/2)})=E_\Gamma(\rho^{(1/2)})=E_W(\rho^{(1/2)})=\log_2(3/2)<\log_2(5/3)=E_N(\rho^{(1/2)}).E1​(ρ(1/2))=EΓ,0​(ρ(1/2))=EΓ​(ρ(1/2))=EW​(ρ(1/2))=log2​(3/2)<log2​(5/3)=EN​(ρ(1/2)).

Moreover, ∥TB(P)∥∞=1\|T_B(P)\|_\infty=1∥TB​(P)∥∞​=1, so the projector lower bound is −log⁡2∥TB(P)∥∞=0<E1(ρ(1/2))-\log_2\|T_B(P)\|_\infty=0<E_1(\rho^{(1/2)})−log2​∥TB​(P)∥∞​=0<E1​(ρ(1/2)). This genuinely mixed example makes the first three comparison inequalities equalities. LOCC achievability remains open in the source.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P83
Formal statement
noncomputable section

open scoped Matrix ComplexConjugate ComplexOrder

open Filter

namespace QAlgorithms.Papers.Independent.Intakethird100.P83

open QAlgorithms.Papers.Independent.Support50.P11 (Loewner)

open QAlgorithms.Papers.Independent.Dependency50.P32 (partialTranspose)

open QAlgorithms.Papers.Independent.Information100.P34 (supportProjector)

variable {A B C D : Type*}

variable [Fintype A] [Fintype B] [Fintype C] [Fintype D]

variable [DecidableEq A] [DecidableEq B] [DecidableEq C] [DecidableEq D]

/-- Mixed-state coincidence and failure of the R=P choice, PDF p.5,
with values from Proposition 5 on p.4. No LOCC achievability is asserted. -/
theorem deterministicMixedTightness :
    oneCopyExact (rhoAlpha (1/2)) = Real.logb 2 (3/2) ∧
    exactRegularized (rhoAlpha (1/2)) = Real.logb 2 (3/2) ∧
    entanglementGamma (rhoAlpha (1/2)) = Real.logb 2 (3/2) ∧
    entanglementW (rhoAlpha (1/2)) = Real.logb 2 (3/2) ∧
    entanglementN (rhoAlpha (1/2)) = Real.logb 2 (5/3) ∧
    Real.logb 2 (3/2) < Real.logb 2 (5/3) ∧
    complexSpectralNorm (partialTranspose (supportProjector (rhoAlpha (1/2)))) = 1 ∧
    -Real.logb 2 (complexSpectralNorm (partialTranspose (supportProjector (rhoAlpha (1/2))))) = 0 ∧
    0 < oneCopyExact (rhoAlpha (1/2)) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P83

end
Source
Improved Semidefinite Programming Upper Bound on Distillable Entanglement, arXiv:1601.07940v4, PDF p. 5, Unnumbered result: mixed-state coincidence and failure of the projector choice
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What the Lean code literally says, in plain math · gpt-6.1-sol

On C3⊗C3\mathbb C^3\otimes\mathbb C^3C3⊗C3, with standard basis ∣ij⟩|ij\rangle∣ij⟩, define ρ=16∑i<j(∣ij⟩+∣ji⟩)(⟨ij∣+⟨ji∣)\rho=\tfrac16\sum_{i<j}(|ij\rangle+|ji\rangle)(\langle ij|+\langle ji|)ρ=61​∑i<j​(∣ij⟩+∣ji⟩)(⟨ij∣+⟨ji∣), and let PρP_\rhoPρ​ be the orthogonal projector onto its range. For a bipartite matrix XXX, define X(a,b),(a′,b′)Γ=X(a,b′),(a′,b)X^\Gamma_{(a,b),(a',b')}=X_{(a,b'),(a',b)}X(a,b),(a′,b′)Γ​=X(a,b′),(a′,b)​, ∥X∥1=Re⁡tr⁡X†X\|X\|_1=\operatorname{Re}\operatorname{tr}\sqrt{X^\dagger X}∥X∥1​=RetrX†X​, and let ∥⋅∥op\|\cdot\|_{\mathrm{op}}∥⋅∥op​ denote the Euclidean operator norm. Define FX(k)F_X(k)FX​(k) as the real supremum of Re⁡tr⁡(XQ)\operatorname{Re}\operatorname{tr}(XQ)Retr(XQ) over QQQ satisfying k>0k>0k>0, 0⪯Q⪯I0\preceq Q\preceq I0⪯Q⪯I, and −k−1I⪯QΓ⪯k−1I-k^{-1}I\preceq Q^\Gamma\preceq k^{-1}I−k−1I⪯QΓ⪯k−1I, where ⪯\preceq⪯ denotes positive semidefinite difference. Put D(X)=sup⁡{log⁡2k:k∈R, k>0, FX(k)=1}D(X)=\sup\{\log_2 k:k\in\mathbb R,\ k>0,\ F_X(k)=1\}D(X)=sup{log2​k:k∈R, k>0, FX​(k)=1}, Dreg(X)=sup⁡m≥1D(X⊗m)/mD_{\mathrm{reg}}(X)=\sup_{m\ge1}D(X^{\otimes m})/mDreg​(X)=supm≥1​D(X⊗m)/m, and Γ(X)=sup⁡{r∈R:FX⊗n(2nr)→1}\Gamma(X)=\sup\{r\in\mathbb R:F_{X^{\otimes n}}(2^{nr})\to1\}Γ(X)=sup{r∈R:FX⊗n​(2nr)→1}, without restricting rrr to be nonnegative; tensor powers are defined entrywise by products, with zeroth power the scalar 111. Set W(X)=log⁡2sup⁡RRe⁡tr⁡(XΓR)W(X)=\log_2\sup_R\operatorname{Re}\operatorname{tr}(X^\Gamma R)W(X)=log2​supR​Retr(XΓR), where RRR is Hermitian, ∥R∥op≤1\|R\|_{\mathrm{op}}\le1∥R∥op​≤1, and RΓ⪰0R^\Gamma\succeq0RΓ⪰0, and set N(X)=log⁡2∥XΓ∥1N(X)=\log_2\|X^\Gamma\|_1N(X)=log2​∥XΓ∥1​. All these suprema are real-valued. Then

D(ρ)=Dreg(ρ)=Γ(ρ)=W(ρ)=log⁡232,N(ρ)=log⁡253,log⁡232<log⁡253,D(\rho)=D_{\mathrm{reg}}(\rho)=\Gamma(\rho)=W(\rho)=\log_2\tfrac32,\qquad N(\rho)=\log_2\tfrac53,\qquad \log_2\tfrac32<\log_2\tfrac53,D(ρ)=Dreg​(ρ)=Γ(ρ)=W(ρ)=log2​23​,N(ρ)=log2​35​,log2​23​<log2​35​,

and additionally

∥PρΓ∥op=1,−log⁡2∥PρΓ∥op=0,0<D(ρ).\|P_\rho^\Gamma\|_{\mathrm{op}}=1,\qquad -\log_2\|P_\rho^\Gamma\|_{\mathrm{op}}=0,\qquad 0<D(\rho).∥PρΓ​∥op​=1,−log2​∥PρΓ​∥op​=0,0<D(ρ).
Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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