Appendix E.2, proof of Proposition 6, p. 52 — ζ(n; λ̲) − ζ(n; λ̄) = 2γ(λ̲ − λ̄)(2n − 1) < 0 for n > 1/2 (corrected value)

Initializing...

Appendix E.2, proof of Proposition 6, p. 52 — ζ(n; λ̲) − ζ(n; λ̄) = 2γ(λ̲ − λ̄)(2n − 1) < 0 for n > 1/2 (corrected value) · Prove2Me