lean_workbook_plus_63650
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
If is the probability Amy wins at time she serves or hits, and is defined similarly for Bob, then and . Solve this system for .
Why this node was retired
The posted statement is
theorem lean_workbook_plus_63650 (a b : ℝ) (h₁ : a = 0.3 + 0.6 * (1 - b)) (h₂ : b = 0.35 + 0.45 * (1 - a)) : a = 0.5753424657534247 := by sorry
Conclude a=42/73 exactly; if retaining the finite decimal, state a justified error bound instead of equality.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
Conclude a=42/73 exactly; if retaining the finite decimal, state a justified error bound instead of equality.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_63650 (a b : ℝ) (h₁ : a = 0.3 + 0.6 * (1 - b)) (h₂ : b = 0.35 + 0.45 * (1 - a)) : a = 0.5753424657534247 := by sorry