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For a candidate u and a logarithm μ algebraic over ℚ(u): uμ is real exactly when μ ∈ ℚū, and uμ is never purely imaginary

Proved
DiazModulus.candidate_log_mul_real_iff_rat_conj

by carlok · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let uuu be a candidate for Diaz's conjecture (DiazModulus.IsCandidate: u≠0u \neq 0u=0 with ∣u∣|u|∣u∣ and eue^ueu algebraic), and let μ≠0\mu \neq 0μ=0 be a logarithm of an algebraic number that is algebraic over Q[u]\mathbb{Q}[u]Q[u]. Then uμu\muuμ is real if and only if μ=quˉ\mu = q\bar uμ=quˉ for some q∈Qq \in \mathbb{Q}q∈Q, and uμu\muuμ is never purely imaginary.

So among the logarithms algebraic over Q(u)\mathbb{Q}(u)Q(u), the conjugate uˉ\bar uuˉ is, up to a rational factor, the only one whose product with uuu lies on an axis, whether or not that product is algebraic. Compare DiazModulus.candidate_norm_div_log_not_log, which concerns the factorisations of ∣u∣2|u|^2∣u∣2 itself.

Proof. A candidate lies on neither axis: there uˉ=±u\bar u = \pm uuˉ=±u, so u2=±∣u∣2u^2 = \pm|u|^2u2=±∣u∣2 would be algebraic, against Hermite–Lindemann (DiazModulus.hermite_lindemann_holds). Since uˉ=∣u∣2/u\bar u = |u|^2/uuˉ=∣u∣2/u with ∣u∣2|u|^2∣u∣2 algebraic, uˉ\bar uuˉ is algebraic over Q[u]\mathbb{Q}[u]Q[u], and so is μˉ\bar\muμˉ​, which is algebraic over Q[uˉ]\mathbb{Q}[\bar u]Q[uˉ]. Hence u,μ,uˉ,μˉu, \mu, \bar u, \bar\muu,μ,uˉ,μˉ​ generate an algebra of transcendence degree at most one (Transcendence.trdeg_adjoin_le_one_of_isAlgebraic_adjoin). If uμu\muuμ is real, DiazModulus.log_mul_real_trichotomy_of_trdeg_one leaves only μ∈Quˉ\mu \in \mathbb{Q}\bar uμ∈Quˉ; conversely u⋅quˉ=q∣u∣2u \cdot q\bar u = q|u|^2u⋅quˉ=q∣u∣2 is real. If uμu\muuμ were purely imaginary, DiazModulus.log_mul_imaginary_mixed_of_trdeg_one would put uuu on an axis.

Novelty. Not asserted. In Diaz's reading of (Qr2) (2007, p. 377), Rℓ∩L=Qℓ\mathbb{R}\ell \cap \mathcal{L} = \mathbb{Q}\ellRℓ∩L=Qℓ and iRℓ∩L={0}i\mathbb{R}\ell \cap \mathcal{L} = \{0\}iRℓ∩L={0}; this node is that reading at ℓ=uˉ\ell = \bar uℓ=uˉ, proved for the logarithms algebraic over Q(u)\mathbb{Q}(u)Q(u). It concerns a candidate, so it is vacuous if Diaz's conjecture holds. Not found in the sources read.

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem candidate_log_mul_real_iff_rat_conj (u : ℂ) (hu : IsCandidate u) (μ : ℂ) (hμ : μ ≠ 0)
    (heμ : IsAlgebraic ℚ (Complex.exp μ))
    (hμu : IsAlgebraic (↥(Algebra.adjoin ℚ ({u} : Set ℂ))) μ) :
    ((u * μ).im = 0 ↔ ∃ q : ℚ, μ = (q : ℂ) * conj u) ∧ (u * μ).re ≠ 0 := by
  sorry

end DiazModulus
Source
The candidate case of the transcendence-degree-one form of Diaz's conjecture (Qr2) (G. Diaz, Produits et quotients de combinaisons linéaires de logarithmes de nombres algébriques : conjectures et résultats partiels, J. Théor. Nombres Bordeaux 19 (2007), 373–391, pp. 376–377, the reading ℝℓ ∩ ℒ = ℚℓ, iℝℓ ∩ ℒ = {0} at ℓ = ū), through `DiazModulus.log_mul_real_trichotomy_of_trdeg_one` and `DiazModulus.log_mul_imaginary_mixed_of_trdeg_one`. Not found in the sources read. Formal proof: Diaz modulus mission, 2 October 2026 (C. Perassi).

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