Exact CHSH saddle point and all three strengths
OpenQAlgorithms.Papers.Independent.Intakethird100.P80.chsh_strengthFor the fixed CHSH experiment, outcomes are and the three settings favor equal outcomes, while favors unequal outcomes. Each favored outcome has probability and each other outcome has probability . Let put probability on each assignment in coordinate order , and zero on all others. Let be uniform on the four settings.
The pair is a saddle point in both the correlated and product games. The local strategy is an equalizer, and
This evaluates the strength of this specified experiment, without optimizing quantum states or measurement directions.
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P80
noncomputable section
namespace QAlgorithms.Papers.Independent.Intakethird100.P80
open scoped BigOperators ENNReal Topology Classical
open MeasureTheory Filter
/-- PDF pp.6,9,14–15,18,21: the specified CHSH saddle and all three EXACT strengths.
The decimal 0.0462738469 is not asserted as an exact value. -/
theorem chsh_strength :
chshLocal ∈ stdSimplex ℝ (Potential BellScenario) ∧
Saddle chshTable (stdSimplex ℝ (Settings BellScenario)) (uniformSettings BellScenario) chshLocal ∧
Saddle chshTable (productSettings BellScenario) (uniformSettings BellScenario) chshLocal ∧
(∀ s : Sigma BellScenario, statisticalPayoff chshTable s.1 chshLocal =
statisticalPayoff chshTable (uniformSettings BellScenario) chshLocal) ∧
uniformStrength chshTable = uncorrelatedStrength chshTable ∧
uncorrelatedStrength chshTable = correlatedStrength chshTable ∧
correlatedStrength chshTable = statisticalPayoff chshTable (uniformSettings BellScenario) chshLocal ∧
correlatedStrength chshTable = ENNReal.ofReal (
2 * (1 / 4 + Real.sqrt 2 / 8) * Real.logb 2 ((1 / 4 + Real.sqrt 2 / 8) / (3 / 8)) +
2 * (1 / 4 - Real.sqrt 2 / 8) * Real.logb 2 ((1 / 4 - Real.sqrt 2 / 8) / (1 / 8))) := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P80
end
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What the Lean code literally says, in plain math · gpt-6.1-sol
Consider two parties, each with settings and outcomes in . Write for a setting pair, for an outcome pair, and for an assignment of an outcome to each party’s every setting. Let and be the probability simplices on setting pairs and such assignments, respectively, and let consist of distributions for some probability vectors . Define , and define on the eight assignments
with otherwise. Put and , and define if , and otherwise. For an assignment distribution , let . For and , define by setting and : its value is if some satisfies and , and otherwise it is
viewed in . Define , , and . The declaration asserts that ; for each of the two choices and , one has , , for every , and for every ; moreover, for every , and
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.