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Row-profile census for diagonal-222 rows of an orbit-matrix candidate

Proved
Conway99.diag_two_offdiag_profile

by WillR · Sep 7, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsconway-99orbit-matrixstrongly-regular-graphs

Let CCC be a 9×99\times 99×9 matrix over N\mathbb{N}N satisfying the Conway99 orbit-matrix equations: CCC is symmetric, every row sums to 141414, and (C2)ij+cij(C^2)_{ij} + c_{ij}(C2)ij​+cij​ equals 343434 on the diagonal and 222222 off the diagonal. For a row iii with diagonal entry cii=2c_{ii} = 2cii​=2, the eight off-diagonal entries sum to 121212 with square-sum 282828. Their value multiset is then exactly one of {0,0,1,1,2,2,3,3}\{0,0,1,1,2,2,3,3\}{0,0,1,1,2,2,3,3} or {0,1,1,1,1,2,2,4}\{0,1,1,1,1,2,2,4\}{0,1,1,1,1,2,2,4}, stated as fiber counts over the value classes 000 through 555 (larger entries are excluded by the square sum). In particular every diagonal-222 row contains an off-diagonal zero. This is the diagonal-222 case of the row-profile census feeding the trace-101010 branch of Wilbrink's Theorem 5.

Preamble
import Mathlib.Data.Matrix.Basic
import Mathlib.Algebra.BigOperators.Fin
Formal statement
open scoped BigOperators

namespace Conway99

/-
  Row-profile census for diagonal-2 rows of a Conway99 orbit-matrix
  candidate. Machine-verified census (2026-09-08): eight off-diagonal
  entries with sum 12 and square-sum 28 form exactly the multisets
  {0,0,1,1,2,2,3,3} or {0,1,1,1,1,2,2,4}. Stated as fiber counts over the
  value classes 0..5 (entries above 5 are excluded by the square sum).
  Research infrastructure for `no_orbit_matrix_ten_of_no_four`; not an
  upload candidate until checked in the exact pinned environment.
-/
theorem diag_two_offdiag_profile
    (C : Matrix (Fin 9) (Fin 9) ℕ) (hsymm : ∀ i j, C i j = C j i)
    (hrow : ∀ i, ∑ j, C i j = 14)
    (hsq : ∀ i j, (∑ k, C i k * C k j) + C i j = (if i = j then 12 else 0) + 22)
    (i : Fin 9) (hi : C i i = 2) :
    ((((Finset.univ.erase i).filter (fun k => C i k = 0)).card = 2 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 1)).card = 2 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 2)).card = 2 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 3)).card = 2 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 4)).card = 0 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 5)).card = 0) ∨
     (((Finset.univ.erase i).filter (fun k => C i k = 0)).card = 1 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 1)).card = 4 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 2)).card = 2 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 3)).card = 0 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 4)).card = 1 ∧
      ((Finset.univ.erase i).filter (fun k => C i k = 5)).card = 0)) := by sorry

end Conway99
Source
H. A. Wilbrink, 'On the (99,14,1,2) strongly regular graph', EUT Report 84-WSK-03, 1984, Theorem 5, pp. 350-354, https://pure.tue.nl/ws/files/2449333/256699.pdf ; row-moment census for the trace-10, no-four branch.

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