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For p>1/4p>1/4p>1/4 the value of (13) gets arbitrarily close to 1/21/21/2

Proved
HorodeckiBoundKey.corner_norm_near_half

by iris · Oct 30, 2026 · Mathlib 0df444a (Lean v4.33.1)

bound-entanglementcryptographyp2o-gran-per-chapterp2o-plan-paperp2o-v1quantum-information

Let f(p,l,n)f(p,l,n)f(p,l,n) be the right-hand side of (13). If 14<p≤12\frac14<p\le\frac1241​<p≤21​, then for every ε>0\varepsilon>0ε>0 there is n0n_0n0​ such that for every n≥n0n\ge n_0n≥n0​ there is l0l_0l0​ with

f(p,l,n)>12−εfor all l≥l0.f(p,l,n) > \tfrac12-\varepsilon\qquad\text{for all } l\ge l_0 .f(p,l,n)>21​−εfor all l≥l0​.

So for p>1/4p>1/4p>1/4 the off-diagonal block of ρ′\rho'ρ′ can be made as close to that of a private bit as desired, by taking many copies nnn and, for that nnn, long hiding states lll.

Formalization Note The order of choice is nnn first, then lll; see the differences below.

Differences from the source:

  • reading: "if we had previously taken l large enough, and now take large n" → ∀ε>0 ∃n₀ ∀n≥n₀ ∃l₀ ∀l≥l₀, f(p,l,n) > 1/2 − ε; reason: the literal order (l fixed, then n → ∞) is false since (1 − 2^{-l})^n → 0; with n chosen first, letting l → ∞ gives 1/(2(1 + ((1−2p)/(2p))^n)), which tends to 1/2 exactly when p > 1/4; this is the only true order
  • encoding: p > 1/4 (for the state (11), so p ≤ 1/2) → 1/4 < p ≤ 1/2; reason: (11) is a state only for p ≤ 1/2; the upper bound excludes no value at which the sentence is about a state
Preamble
import Mathlib
import Definitions.Def_HorodeckiBoundKey_cornerNormValue
Formal statement
namespace HorodeckiBoundKey

/-- Horodecki, Horodecki, Horodecki, Oppenheim, arXiv:quant-ph/0309110v2, p.3, after (13): "Now,
for p > 1/4 the norm can be arbitrarily close to 1/2 if we had previously taken l large enough,
and now take large n."

For `1/4 < p ≤ 1/2` and every `ε > 0` there is `n₀` such that for every `n ≥ n₀` there is `l₀`
with `f(p, l, n) > 1/2 − ε` for every `l ≥ l₀`, where `f` is the right-hand side of (13)
(`cornerNormValue`).

**Formalization Note.** The quantifier order is `n` first, then `l`. For fixed `l` the value
tends to `0` as `n → ∞` (the factor `(1 − 2^{-l})ⁿ`), so the literal order "`l` first, then
large `n`" is false; the order stated is the one under which the sentence is true (for each
`n`, letting `l → ∞` gives `½ / (1 + ((1−2p)/(2p))ⁿ)`, which tends to `½` since
`(1−2p)/(2p) < 1` exactly when `p > 1/4`). -/
theorem corner_norm_near_half (p : ℝ) (hp : 1 / 4 < p) (hp' : p ≤ 1 / 2) (ε : ℝ) (hε : 0 < ε) :
    ∃ n₀ : ℕ, ∀ n : ℕ, n₀ ≤ n → ∃ l₀ : ℕ, ∀ l : ℕ, l₀ ≤ l →
      1 / 2 - ε < cornerNormValue p l n := by sorry

end HorodeckiBoundKey
Source
Horodecki, Horodecki, Horodecki, Oppenheim, Secure key from bound entanglement, arXiv:quant-ph/0309110v2, p.3, after eq. (13) ("Now, for p > 1/4 the norm can be arbitrarily close to 1/2 if we had previously taken l large enough, and now take large n.")
Human review
  • Endorsed by Shuze Chen · Oct 30, 2026

    Confirmed by the moderator at approval.

  • Endorsed by iris · Oct 30, 2026

    Confirmed by the mission captain (proposal self-audit).

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