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Track obstruction with diverging amplified gap (Erdős 624)

Proved
Erdos624.trackBad_obstruction_diverging

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Let H(n)H(n)H(n) be as in Erdős Problem 624. Say TrackBad(n,m,s)\mathrm{TrackBad}(n,m,s)TrackBad(n,m,s) holds if for every family of maps gB:P(U)→Ug_B:\mathcal P(U)\to UgB​:P(U)→U (∣U∣=n|U|=n∣U∣=n) indexed by the subsets BBB of an sss-set, there are Y⊆UY\subseteq UY⊆U with ∣Y∣=m|Y|=m∣Y∣=m and u∈Uu\in Uu∈U with u∉{gB(A):A⊆Y}u\notin\{g_B(A):A\subseteq Y\}u∈/{gB​(A):A⊆Y} for every BBB. By Erdos624.track_amplification, TrackBad(n,m,s)\mathrm{TrackBad}(n,m,s)TrackBad(n,m,s) implies H(n+s)>m+sH(n+s)>m+sH(n+s)>m+s for n≥1n\ge1n≥1. Theorem. Let k≥1k\ge1k≥1 and let s=⌊log⁡2(k(k+1))⌋+1s=\lfloor\log_2(k(k+1))\rfloor+1s=⌊log2​(k(k+1))⌋+1, the least sss with 2s>k(k+1)2^s>k(k+1)2s>k(k+1). Then TrackBad(2k,k,s)\mathrm{TrackBad}(2^k,k,s)TrackBad(2k,k,s) is false, although

k+s−⌈log⁡2(2k+s)⌉ ≥ ⌊log⁡2(k(k+1))⌋→∞.k+s-\lceil\log_2(2^k+s)\rceil\ \ge\ \lfloor\log_2(k(k+1))\rfloor\to\infty.k+s−⌈log2​(2k+s)⌉ ≥ ⌊log2​(k(k+1))⌋→∞.

So m+s−log⁡2(n+s)→∞m+s-\log_2(n+s)\to\inftym+s−log2​(n+s)→∞ alone does not imply TrackBad(n,m,s)\mathrm{TrackBad}(n,m,s)TrackBad(n,m,s), even with only O(log⁡log⁡n)O(\log\log n)O(loglogn) tracks. (With s≥log⁡2ns\ge\log_2 ns≥log2​n tracks this would be trivial, since constant tracks cover UUU.)

Formalization Note. The statement lists: k(k+1)<2sk(k+1)<2^sk(k+1)<2s; minimality of sss; ¬TrackBad(2k,k,s)\neg\mathrm{TrackBad}(2^k,k,s)¬TrackBad(2k,k,s); and ⌊log⁡2(k(k+1))⌋+⌈log⁡2(2k+s)⌉≤k+s\lfloor\log_2(k(k+1))\rfloor+\lceil\log_2(2^k+s)\rceil\le k+s⌊log2​(k(k+1))⌋+⌈log2​(2k+s)⌉≤k+s, using Nat.log/Nat.clog.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem trackBad_obstruction_diverging (k : ℕ) (hk : 1 ≤ k) :
    k * (k + 1) < 2 ^ (Nat.log 2 (k * (k + 1)) + 1) ∧
    (∀ s' < (Nat.log 2 (k * (k + 1)) + 1), 2 ^ s' ≤ k * (k + 1)) ∧
    (¬ ∀ g : Finset (Fin (Nat.log 2 (k * (k + 1)) + 1)) → Finset (Fin (2 ^ k)) → Fin (2 ^ k), ∃ Y : Finset (Fin (2 ^ k)), #Y = k ∧
      ∃ u : Fin (2 ^ k), ∀ B : Finset (Fin (Nat.log 2 (k * (k + 1)) + 1)), ∀ A ∈ Y.powerset, g B A ≠ u) ∧
    Nat.log 2 (k * (k + 1)) + Nat.clog 2 (2 ^ k + (Nat.log 2 (k * (k + 1)) + 1)) ≤ k + (Nat.log 2 (k * (k + 1)) + 1) := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; Claim B3 of claim from a GPT answer relayed by Ethan Cheung (third round, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)

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