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Trace of a product of two diagonalizable operators via their eigenbasis overlaps

Proved
HlawkaSchatten.re_trace_comp_eq_sum_eigenbasis_overlap

by savarin · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

hermitian-operatorshlawka-schattenspectral-theorytrace-identities

Let EEE be a finite-dimensional complex inner-product space, and let A,B:E→EA,B:E\to EA,B:E→E be complex-linear maps with AAA symmetric (self-adjoint), i.e. ⟨Ax,y⟩=⟨x,Ay⟩\langle Ax,y\rangle=\langle x,Ay\rangle⟨Ax,y⟩=⟨x,Ay⟩ for all x,y∈Ex,y\in Ex,y∈E. Let (ei)i∈ι(e_i)_{i\in\iota}(ei​)i∈ι​ and (fj)j∈κ(f_j)_{j\in\kappa}(fj​)j∈κ​ be orthonormal bases of EEE indexed by finite sets ι,κ\iota,\kappaι,κ, and let a:ι→Ra:\iota\to\mathbb Ra:ι→R, b:κ→Rb:\kappa\to\mathbb Rb:κ→R be such that eie_iei​ is an eigenvector of AAA with eigenvalue aia_iai​ (A(ei)=aieiA(e_i)=a_ie_iA(ei​)=ai​ei​) and fjf_jfj​ is an eigenvector of BBB with eigenvalue bjb_jbj​ (B(fj)=bjfjB(f_j)=b_jf_jB(fj​)=bj​fj​), for every i,ji,ji,j. Write the basis overlap ov⁡(ei,fj)=∣⟨ei,fj⟩∣2\operatorname{ov}(e_i,f_j)=|\langle e_i,f_j\rangle|^2ov(ei​,fj​)=∣⟨ei​,fj​⟩∣2. Then

Re⁡tr⁡(A∘B)=∑(i,j)∈ι×κai bj ov⁡(ei,fj).\operatorname{Re}\operatorname{tr}(A\circ B) = \sum_{(i,j)\in\iota\times\kappa} a_i\, b_j\, \operatorname{ov}(e_i,f_j).Retr(A∘B)=(i,j)∈ι×κ∑​ai​bj​ov(ei​,fj​).

This expands the trace of a product of two diagonalizable operators, each given in its own eigenbasis, into a double sum over pairs of eigenvalues weighted by the squared overlaps of the two eigenbases. It is the key spectral-lift step: applied to the Hermitian dilations of two rectangular operators, it turns trace-level Bregman- and Mazur-type comparison quantities into sums, over pairs of eigenvalues, of the purely scalar Bregman/Mazur comparison — which is where dimension-independent constants can come from.

Formalization Note. Only AAA is hypothesized symmetric; BBB is given only through its eigen-relation B(fj)=bjfjB(f_j)=b_jf_jB(fj​)=bj​fj​ with real bbb, not through a separate IsSymmetric hypothesis. This is not a genuinely broader class of operators than symmetric ones — an operator that is diagonal with real eigenvalues in some orthonormal basis is automatically self-adjoint — but the proof below never uses any self-adjointness fact about BBB, only the explicit eigen-data (f,b)(f,b)(f,b), so stating the hypothesis this way records exactly what the argument needs, not a strictly weaker mathematical assumption. The same observation applies to AAA: the eigen-relation A(ei)=aieiA(e_i)=a_ie_iA(ei​)=ai​ei​ already forces AAA to be self-adjoint, so the separately listed hypothesis that AAA is symmetric is likewise implied by the eigen-data, not an independent restriction.

Preamble
import Definitions.Def_HlawkaSchatten_SpectralLift
import Mathlib.Analysis.Calculus.LHopital
import Mathlib.Analysis.Convex.Deriv
import Mathlib.Analysis.Convex.SpecificFunctions.Basic
import Mathlib.Analysis.InnerProductSpace.Basic
import Mathlib.Analysis.InnerProductSpace.Dual
import Mathlib.Analysis.InnerProductSpace.NormPow
import Mathlib.Analysis.InnerProductSpace.PiL2
import Mathlib.Analysis.InnerProductSpace.Trace
import Mathlib.Data.Sign.Basic
import Mathlib.Topology.Compactification.OnePoint.Basic
import Mathlib.Topology.Instances.Sign

/-
Copyright (c) 2026 Ezzeri Esa. All rights reserved.
Released under Apache 2.0 license as described in the file LICENSE.
Authors: Ezzeri Esa
-/

/-!
# Finite Hermitian spectral trace expansions

This file connects the overlap-weighted scalar comparison to traces of
finite-dimensional symmetric complex-linear maps.
-/


open scoped InnerProductSpace
open RCLike
open ComplexConjugate

variable {ι κ E : Type*} [Fintype ι] [Fintype κ]
  [NormedAddCommGroup E] [InnerProductSpace ℂ E]

open HlawkaSchatten
Formal statement
theorem HlawkaSchatten.re_trace_comp_eq_sum_eigenbasis_overlap [FiniteDimensional ℂ E]
    (A B : E →ₗ[ℂ] E) (hA : A.IsSymmetric)
    (e : OrthonormalBasis ι ℂ E) (f : OrthonormalBasis κ ℂ E)
    (a : ι → ℝ) (b : κ → ℝ)
    (he : ∀ i, A (e i) = (a i : ℂ) • e i)
    (hf : ∀ j, B (f j) = (b j : ℂ) • f j) :
    ((A.comp B).trace ℂ E).re =
      ∑ ij : ι × κ, a ij.1 * b ij.2 * orthonormalBasisOverlap e f ij := by sorry
Source
https://github.com/savarin/hlawka-schatten/blob/79aa498bfcf7b22bd91d771fb32ec278e2d4704b/HlawkaSchatten/HermitianSpectral.lean#L326-L357

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