Integrability of for a compactly supported kernel
ProvedVino.integrable_cpow_mulanalytic-number-theoryasymptoticsmellin-transformpnt
Let be continuous with , and let . Then
is integrable on (hence on ), for every exponent — no convergence condition on is needed.
Compact support inside removes both the singularity of at the origin and the growth at infinity, which is why the Mellin transform of such a kernel is entire. Stated in this form, the lemma is the integrability side condition for every manipulation of used in the Mellin calculus of the smoothed cutoff.
Preamble
import Mathlib.Analysis.MellinTransform import Mathlib.Analysis.SpecialFunctions.Pow.Complex import Mathlib.Analysis.Complex.Exponential open Set MeasureTheory Complex
Formal statement
namespace Vino
theorem integrable_cpow_mul {ν : ℝ → ℝ} (contν : Continuous ν) (suppν : ν.support ⊆ Icc (1 / 2) 2) (a : ℂ) :
Integrable (fun x : ℝ => (x : ℂ) ^ a * (ν x : ℂ)) := by sorry
end VinoSource
A. Kontorovich et al., PrimeNumberTheoremAnd, https://github.com/AlexKontorovich/PrimeNumberTheoremAnd/blob/master/PrimeNumberTheoremAnd/MellinCalculus.lean (the `MellinOfSmooth1a/b/c` family and the smoothed cutoff `Smooth1`); H. Davenport, Multiplicative Number Theory, 3rd ed., Springer GTM 74, 2000, Chapter 17 (Perron's formula and the smoothed Chebyshev function).