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Erasure-cost lower bound: a parity certificate must delete a point of each zero-sum triple block (Erdős 624 cross-review)

Proved
Erdos624.erasure_block_lower_bound

by Ethan Cheung · Oct 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Let P1,…,PtP_1,\dots,P_tP1​,…,Pt​ be pairwise disjoint finite sets of coordinates and, for each jjj, let Ej1,Ej2,Ej3⊆PjE^1_j,E^2_j,E^3_j\subseteq P_jEj1​,Ej2​,Ej3​⊆Pj​ satisfy χEj1+χEj2+χEj3=0\chi_{E^1_j}+\chi_{E^2_j}+\chi_{E^3_j}=0χEj1​​+χEj2​​+χEj3​​=0 over F2\mathbb F_2F2​ (relation (Z)). Let RRR be a set of deleted coordinates and www an F2\mathbb F_2F2​-valued form such that every EjiE^i_jEji​ disjoint from RRR has ∑x∈Ejiw(x)=1\sum_{x\in E^i_j}w(x)=1∑x∈Eji​​w(x)=1. Then ∣R∣≥t|R|\ge t∣R∣≥t.

In the cross-review's construction these are the three proper minimal witnesses of a colour uzu_zuz​ in each block, so every successful deletion meets all ttt blocks: σuz(U)≥t\sigma_{u_z}(U)\ge tσuz​​(U)≥t (the lower half of (EC)).

Context: Erdős Problem 624 asks whether H(n)−log⁡2n→∞H(n)-\log_2 n\to\inftyH(n)−log2​n→∞, where H(n)H(n)H(n) is the least mmm such that some f:P(X)→Xf:\mathcal P(X)\to Xf:P(X)→X with ∣X∣=n|X|=n∣X∣=n satisfies f[P(Y)]=Xf[\mathcal P(Y)]=Xf[P(Y)]=X for all ∣Y∣≥m|Y|\ge m∣Y∣≥m. This is an auxiliary finite statement from Sol's Round 12 Step 17 cross-review / resilience analysis of the two-track (PAIR) case. It does not settle Erdős Problem 624, PAIR or Step 17.

Preamble
import Mathlib
open Finset
Formal statement
namespace Erdos624

theorem erasure_block_lower_bound {U : Type*} [DecidableEq U] (t : ℕ) (P : Fin t → Finset U)
    (hP : ∀ i j, i ≠ j → Disjoint (P i) (P j))
    (E1 E2 E3 : Fin t → Finset U) (h1 : ∀ j, E1 j ⊆ P j) (h2 : ∀ j, E2 j ⊆ P j)
    (h3 : ∀ j, E3 j ⊆ P j)
    (hZ : ∀ j x, ((if x ∈ E1 j then 1 else 0) + (if x ∈ E2 j then 1 else 0) +
      (if x ∈ E3 j then 1 else 0) : ZMod 2) = 0)
    (R : Finset U) (w : U → ZMod 2)
    (hw : ∀ j, (Disjoint (E1 j) R → ∑ x ∈ E1 j, w x = 1) ∧
      (Disjoint (E2 j) R → ∑ x ∈ E2 j, w x = 1) ∧ (Disjoint (E3 j) R → ∑ x ∈ E3 j, w x = 1)) :
    t ≤ #R := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); Round 12: Sol's 'Step 17: First-Round Cross-Review' and 'Step 17: resilient relations below the top layer'; derived from GPT 6.1 Sol's analysis, relayed by Ethan Cheung; hand-checked and Lean-verified by Grok Bot for Ethan Cheung (Oct 24 2026). Auxiliary result only; does NOT settle PAIR / Step 17 / #624.

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