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II.D: replacing nonempty coherent pulses by single photons makes distinct source sequences orthogonal

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QAlgorithms.Papers.Independent.Intakethird100.P33.fockSubstitution

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

For n≥0n\ge0n≥0 two-bin source blocks, let w∈{0,1,d}nw\in\{0,1,d\}^nw∈{0,1,d}n be a preparation word, where ddd denotes a decoy. Replace every occupied coherent pulse by a one-photon Fock state and every blocked pulse by vacuum. The three block symbols then become ∣1,0⟩|1,0\rangle∣1,0⟩, ∣0,1⟩|0,1\rangle∣0,1⟩, and ∣1,1⟩|1,1\rangle∣1,1⟩. Let ∣Fw⟩|F_w\rangle∣Fw​⟩ be their full multimode number-basis product. Then

∥Fw∥=1,⟨Fw∣Fv⟩={1,w=v,\0,w≠v.\|F_w\|=1,\qquad\langle F_w|F_v\rangle=\begin{cases}1,&w=v,\0,&w\ne v.\end{cases}∥Fw​∥=1,⟨Fw​∣Fv​⟩={1,​w=v,\0,​w=v.​

For n=0n=0n=0, the sole empty word has norm one. This identifies the mathematical obstruction in the proposed direct Fock substitution, without claiming an impossibility theorem for other single-photon protocols.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P33
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Intakethird100.P33

open scoped BigOperators ENNReal

open QAlgorithms.RealRegisters (Hilbert)

open QAlgorithms.Papers.Independent.Dependency50.P33 (IsDensity rankOne)

open QAlgorithms.Papers.Independent.Dependency50.P39 (coherentCoefficient)

open QAlgorithms.Papers.Independent.Support50.P48 (vacuumAmplitude)

open QAlgorithms.Papers.Independent.Next46.P32 (FockPOVM realFockTracePair)

open QAlgorithms.Papers.Independent.Dependency50.P34
  (TwoModeFock fockKet photonMean)

open QAlgorithms.Papers.Independent.Frontier18.P14
  (coherentPair coherentPairCoefficients)

attribute [local instance] Classical.propDecidable

attribute [local instance] Classical.decEq

/-- PDF p.3, II.D: replacing every occupied pulse by one photon gives orthogonal
number-basis words, including normalization of the unique zero-block word. -/
theorem fockSubstitution (n : ℕ) :
    (∀ w : Fin n → Fin 3, ‖substitutedWord w‖ = 1) ∧
    (∀ w v : Fin n → Fin 3,
      inner ℂ (substitutedWord w) (substitutedWord v) = if w = v then 1 else 0) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P33

end
Source
Towards practical and fast Quantum Cryptography, arXiv:quant-ph/0411022v1, PDF p. 3, II.D, single-photon remark
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every natural number nnn and every word w:{0,…,n−1}→{0,1,2}w:\{0,\ldots,n-1\}\to\{0,1,2\}w:{0,…,n−1}→{0,1,2}, define an occupation configuration sw:{0,…,n−1}×{false,true}→Ns_w:\{0,\ldots,n-1\}\times\{\mathrm{false},\mathrm{true}\}\to\mathbb Nsw​:{0,…,n−1}×{false,true}→N by assigning the pair of occupations (1,0)(1,0)(1,0) to the symbol 000, (0,1)(0,1)(0,1) to the symbol 111, and (1,1)(1,1)(1,1) to the symbol 222, with the false coordinate listed first. Let ewe_wew​ be the vector in ℓ2(({0,…,n−1}×{false,true})→N;C)\ell^2((\{0,\ldots,n-1\}\times\{\mathrm{false},\mathrm{true}\})\to\mathbb N;\mathbb C)ℓ2(({0,…,n−1}×{false,true})→N;C) whose coefficient is one at sws_wsw​ and zero elsewhere. Then every ewe_wew​ has norm one, and for every pair of words w,vw,vw,v,

⟨ew,ev⟩={1,w=v,0,w≠v.\langle e_w,e_v\rangle= \begin{cases} 1,&w=v,\\ 0,&w\ne v. \end{cases}⟨ew​,ev​⟩={1,0,​w=v,w=v.​

This includes n=0n=0n=0, when there is a single empty word and a single occupation configuration.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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