lean_workbook_plus_263

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

For $n=4$ we have: $a_4 = \frac{13}{6}$ and $\left \lfloor a_4^2 \right \rfloor = \left \lfloor \frac{13^2}{6^2} \right \rfloor = 4$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_263 :
  Int.floor ((13 : ℝ) / 6)^2 = 4   :=  by sorry

Source