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Theorem 11.28 — Lebesgue's monotone convergence theorem

Proved
Rudin.ch11_monotone_convergence

by Lucas · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysismeasure-theory

If 0≤f1≤f2≤⋯0 \le f_1 \le f_2 \le \cdots0≤f1​≤f2​≤⋯ are measurable and fn(x)→f(x)f_n(x) \to f(x)fn​(x)→f(x) for every xxx, then ∫fn dμ→∫f dμ\int f_n\,d\mu \to \int f\,d\mu∫fn​dμ→∫fdμ.

Preamble
import Mathlib
import Definitions.Def_Rudin_ch11_L2

open Filter Topology MeasureTheory
open scoped ENNReal
Formal statement
namespace Rudin

/-- Rudin, Theorem 11.28 (Lebesgue's monotone convergence theorem): if `0 ≤ f 0 ≤ f 1 ≤ ⋯` are
measurable and converge pointwise to `g`, then the integrals converge to the integral of
`g`. -/
theorem ch11_monotone_convergence {X : Type*} [MeasurableSpace X] (μ : Measure X)
    (f : ℕ → X → ℝ≥0∞) (hf : ∀ n, Measurable (f n)) (hmono : ∀ x, Monotone fun n => f n x)
    (g : X → ℝ≥0∞) (hg : ∀ x, Tendsto (fun n => f n x) atTop (𝓝 (g x))) :
    Tendsto (fun n => ∫⁻ x, f n x ∂μ) atTop (𝓝 (∫⁻ x, g x ∂μ)) := by sorry

end Rudin
Source
Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976, Chapter 11, p. 319, Theorem 11.28
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What the Lean code literally says, in plain math · Aristotle (Harmonic)

Let XXX be a measurable space with measure μ\muμ, and let f0,f1,⋯:X→[0,∞]f_0,f_1,\dots : X \to [0,\infty]f0​,f1​,⋯:X→[0,∞] be measurable functions into the extended nonnegative reals such that for every xxx the sequence n↦fn(x)n \mapsto f_n(x)n↦fn​(x) is monotone non-decreasing. Let g:X→[0,∞]g : X \to [0,\infty]g:X→[0,∞] be such that for every xxx, fn(x)→g(x)f_n(x) \to g(x)fn​(x)→g(x) in [0,∞][0,\infty][0,∞] (convergence in the order topology, which includes tending to +∞+\infty+∞). Then

∫X−fn dμ  ⟶  ∫X−g dμ(n→∞),\int_X^{-} f_n \, d\mu \;\longrightarrow\; \int_X^{-} g\, d\mu \qquad (n\to\infty),∫X−​fn​dμ⟶∫X−​gdμ(n→∞),

where ∫−\int^{-}∫− denotes the lower Lebesgue integral of a [0,∞][0,\infty][0,∞]-valued function, and convergence is again in [0,∞][0,\infty][0,∞].

Nonnegativity is automatic from the codomain; no measurability of ggg is assumed as a hypothesis, and no finiteness of any integral is required.

Human review
  • Endorsed by Shuze Chen · Sep 13, 2026

  • Endorsed by Lucas · Sep 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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