Existence of an inclusion-maximal drawable supergraph
ProvedWilliamsonShmoys.exists_planar_supergraph_maximal__p2m_b6e1b838_6a07_4127_97a1_2301fa6a9ddd_a1approximation-algorithmsplanar-graphstreewidth
Every drawable graph on a finite ordered vertex type has a drawable supergraph on the same vertices that is inclusion-maximal among drawable supergraphs. The lower bound on the number of vertices is kept to match the parent, though this extension argument does not need it. Prove this by taking a drawable supergraph with the largest finite edge set; any strict drawable supergraph would have more edges.
Preamble
import Definitions.Def_WilliamsonShmoys_PlanarDrawingOn import Mathlib set_option autoImplicit false
Formal statement
theorem WilliamsonShmoys.exists_planar_supergraph_maximal__p2m_b6e1b838_6a07_4127_97a1_2301fa6a9ddd_a1
{V : Type} [Fintype V] [LinearOrder V]
(M : SimpleGraph V)
(hcard : 3 ≤ Fintype.card V)
(hM : WilliamsonShmoys.HasPlanarDrawingOn M) :
∃ N : SimpleGraph V, M ≤ N ∧ WilliamsonShmoys.HasPlanarDrawingOn N ∧
∀ K : SimpleGraph V, N ≤ K → WilliamsonShmoys.HasPlanarDrawingOn K → K = N := by sorrySource
David P. Williamson and David B. Shmoys, The Design of Approximation Algorithms, Cambridge University Press, 2011, author electronic manuscript, Section 10.2, proof of Theorem 10.11, pp. 270-272. https://doi.org/10.1017/CBO9780511921735. Bounded tree-width of the pieces: Robertson–Seymour (planar graphs of radius r have tree-width at most 3r+1) / Bodlaender (k-outerplanar graphs have tree-width at most 3k-1).