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Subcritical Levi-Civita component is strictly star-shaped

Proved
BirkhoffGlobalSection.left_energy_component_radial_derivative_pos

by Mazecto · Oct 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

celestial-mechanicsdynamical-systemshamiltonian-dynamics

Let 0<μ<10<\mu<10<μ<1 and let ccc be below the first critical value, −c<H(L1)-c<H(L_1)−c<H(L1​). Then the selected Levi-Civita component Σμ,c\Sigma_{\mu,c}Σμ,c​ (the component of {Kμ,c=0}\{K_{\mu,c}=0\}{Kμ,c​=0} through the regularized collision) is strictly star-shaped with respect to the origin:

dKμ,c(s) s>0for every s∈Σμ,c.dK_{\mu,c}(s)\,s>0\qquad\text{for every } s\in\Sigma_{\mu,c}.dKμ,c​(s)s>0for every s∈Σμ,c​.

Proof idea: write s=R xs=R\,xs=Rx with ∣x∣=1|x|=1∣x∣=1. Along the ray t↦txt\mapsto t xt↦tx, the energy is negative for 0≤t<R0\le t<R0≤t<R (Proved left_component_radial_interior_negative), and the ray avoids the second collision up to the first positive-energy scale (Proved left_ray_positive_energy_before_second_collision), hence on [0,R][0,R][0,R]. So sss lies in the closure of the negative component through 000 (Proved first_ray_zero_in_left_negative_closure). There the radial derivative ddaK(as)∣a=1\frac{d}{da}K(as)|_{a=1}dad​K(as)∣a=1​ is positive (Proved left_negative_closure_radial_transversality), and by the chain rule it equals dK(s) sdK(s)\,sdK(s)s.

Preamble
import Definitions.Def_BirkhoffGlobalSection
Formal statement
namespace BirkhoffGlobalSection

/-- Below the first critical value, the selected Levi-Civita component is
strictly star-shaped: the radial vector field is positively transverse to it,
in the form `dH_s(s) > 0`. -/
theorem left_energy_component_radial_derivative_pos (μ c : ℝ)
    (hμ0 : 0 < μ) (hμ1 : μ < 1)
    (hc : belowFirstCriticalValue μ c) :
    ∀ s ∈ leftEnergyComponent μ c,
      0 < fderiv ℝ (leviCivitaHamiltonian μ c) s s := by sorry

end BirkhoffGlobalSection
Source
Joung--van Koert, https://arxiv.org/abs/2407.19159v3, Section 4 (star-shapedness of the regularized component); assembled from the Proved platform lemmas named in the statement.

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