lean_workbook_plus_45012

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

$\frac x8+\frac x{12}+\frac x6=2$ so $x=\frac{16}3$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_45012 (x : ℝ) : x/8 + x/12 + x/6 = 2 ↔ x = 16/3   :=  by sorry

Source