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Planar P01 surface integral as an angle integral without regularity assumptions

Proved
RybinAI2026.P01.surface_integral_two_eq_angle_total

by WillR · Sep 30, 2026 · Mathlib c5ea003 (Lean v4.30.0)

integral-inequalitymeasure-theorypolar-coordinatessurface-measure

For every real-valued function on the plane, its totalized integral over the unit circle with the unnormalized P01 surface measure equals the totalized angle integral over (-pi, pi), using the standard cosine-sine parametrization. No continuity or integrability hypothesis is required, so the identity applies directly to directional kernels defined on the sphere.

Preamble
import Mathlib
import Definitions.Def_rybin2026_p01_matrix_integral

open MeasureTheory Metric RybinAI2026.P01
Formal statement
theorem RybinAI2026.P01.surface_integral_two_eq_angle_total (f : Euclidean 2 → ℝ) :
    (∫ u : sphere (0 : Euclidean 2) 1, f u.1 ∂surfaceMeasure 2) =
      ∫ θ in (-Real.pi)..Real.pi,
        f (WithLp.toLp 2 ![Real.cos θ, Real.sin θ]) := by
  sorry
Source
The P01 sphere measure is volume.toSphere. Combining Mathlib's generalized sphere-radial measure-preserving decomposition with planar polar coordinates gives this equality for arbitrary totalized integrals. This stronger form directly supports the directional kernels in the diagonal perpendicular-rank-one restriction of RybinAI2026.P01.matrix_integral_inequality.

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