lean_workbook_plus_8327

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

The condition gives $(x-1)^2+(y-1)^2+(z-1)^2=0$ , yielding reals $x=y=z=1$ .

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_8327 (x y z : ℝ) (h : (x - 1) ^ 2 + (y - 1) ^ 2 + (z - 1) ^ 2 = 0) : x = 1 ∧ y = 1 ∧ z = 1   :=  by sorry

Source