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Chapter 15 algebra: positivity and breakpoint agreement for the two-centre relabelling path

Proved
BookSixth.pair_relabel_line_gap_algebra

by WillR · Sep 30, 2026 · Mathlib c5ea003 (Lean v4.30.0)

book-sixthchapter-15linear-algebra

Elementary algebra for the two-centre relabelling path of Chapter 15. Write τ(t)=max⁡0 (min⁡t 1)\tau(t)=\max 0\,(\min t\,1)τ(t)=max0(mint1), L(a,t)=a+1−aτ(t)L(a,t)=a+1-a\tau(t)L(a,t)=a+1−aτ(t) and R(b,t)=b−1+(3−b)τ(t)R(b,t)=b-1+(3-b)\tau(t)R(b,t)=b−1+(3−b)τ(t) for the left and right endpoints of the moving middle interval, and gin(a,b)=b−a−2g_{\mathrm{in}}(a,b)=b-a-2gin​(a,b)=b−a−2 and gout(a,b,t)=R(b,t)−L(a,t)g_{\mathrm{out}}(a,b,t)=R(b,t)-L(a,t)gout​(a,b,t)=R(b,t)−L(a,t) for the interior gap and the gap after time ttt. This record isolates the purely algebraic core needed to build the piecewise-linear path of homeomorphisms of R\mathbb{R}R that carries the two ordered centres 3i3i3i and 3j3j3j onto 000 and 333. It states: τ\tauτ is continuous with τ0=0\tau 0 = 0τ0=0, τ1=1\tau 1 = 1τ1=1 and 0≤τt≤10\le\tau t\le 10≤τt≤1; both gaps are strictly positive whenever 3≤b−a3\le b-a3≤b−a; the moving gap satisfies the exact identity gout=1+(b−a−3)(1−τt)g_{\mathrm{out}}=1+(b-a-3)(1-\tau t)gout​=1+(b−a−3)(1−τt), so the motion closes the slack b−a−3b-a-3b−a−3 linearly and never collapses the gap; and the four breakpoint agreement identities that make the forward and backward piecewise-linear maps agree where their pieces meet. Every clause is an equality or a positivity fact about explicit real expressions, so the record is independent of any topological content and can be imported by the later reduction that supplies continuity, the two-sided inverse, and the endpoint laws.

Preamble
import Mathlib
Formal statement
theorem BookSixth.pair_relabel_line_gap_algebra :
    (Continuous (fun t : ℝ => max 0 (min t 1))) ∧
    ((max 0 (min 0 1)) = 0) ∧
    ((max 0 (min 1 1)) = 1) ∧
    (∀ t : ℝ, 0 ≤ max 0 (min t 1)) ∧
    (∀ t : ℝ, max 0 (min t 1) ≤ 1) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → 0 < b - a - 2) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → ∀ t : ℝ,
      0 < (b - 1 + (3 - b) * max 0 (min t 1)) - (a + 1 - a * max 0 (min t 1))) ∧
    (∀ a b t : ℝ,
      (b - 1 + (3 - b) * max 0 (min t 1)) - (a + 1 - a * max 0 (min t 1))
        = 1 + (b - a - 3) * (1 - max 0 (min t 1))) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → ∀ t : ℝ,
      a + 1 - a * max 0 (min t 1)
        = (a + 1 - a * max 0 (min t 1))
          + ((a + 1 - (a + 1)) * ((b - 1 + (3 - b) * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))) / (b - a - 2))) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → ∀ t : ℝ,
      (a + 1 - a * max 0 (min t 1))
          + ((b - 1 - (a + 1)) * ((b - 1 + (3 - b) * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))) / (b - a - 2))
        = b - 1 + (3 - b) * max 0 (min t 1)) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → ∀ t : ℝ,
      a + 1 + (((b - 1 + (3 - b) * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))) * (b - a - 2)
          / ((b - 1 + (3 - b) * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))))
        = (b - 1 + (3 - b) * max 0 (min t 1))
          - (3 - b) * max 0 (min t 1)) ∧
    (∀ {a b : ℝ}, 3 ≤ b - a → ∀ t : ℝ,
      (a + 1 - a * max 0 (min t 1)) + a * max 0 (min t 1)
        = a + 1 + (((a + 1 - a * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))) * (b - a - 2)
          / ((b - 1 + (3 - b) * max 0 (min t 1))
            - (a + 1 - a * max 0 (min t 1))))) := by sorry
Source
Corrected algebraic core for Chapter 15, Theorem 1 of Aigner and Ziegler, Proofs from THE BOOK, Sixth Edition (2018), p. 130, https://doi.org/10.1007/978-3-662-57265-8_15. The two centres 3i<3j3i<3j3i<3j are separated by at least 333 because i<ji<ji<j, which is exactly the hypothesis 3≤b−a3\le b-a3≤b−a under which both gaps are positive and every division below is legal. The identity gout=1+(b−a−3)(1−τt)g_{\mathrm{out}}=1+(b-a-3)(1-\tau t)gout​=1+(b−a−3)(1−τt) is the reason the motion is well defined for all time: the gap retains its initial value 111 plus the unclosed portion b−a−3b-a-3b−a−3 of the original slack, and reaches exactly 111 when τt=1\tau t=1τt=1, leaving the two unit circles adjacent. The four agreement identities are the continuity conditions at the breakpoints a+1a+1a+1 and b−1b-1b−1; they are stated for both the forward and the backward piecewise-linear maps because both are needed to show they are inverse homeomorphisms.

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