Coherent two three forms common quadratic
ProvedD1Bound5.coherent_two_three_forms_common_quadraticdiophantine-tuplesnumber-theory
Two vanishing coherent triple forms sharing their first two roots produce one quadratic taking all four prescribed values. Only the difference of the two shared anchors is divided out.
Preamble
import Mathlib.Algebra.BigOperators.NatAntidiagonal import Mathlib.Algebra.QuadraticAlgebra.Basic import Mathlib.Algebra.Ring.Basic import Mathlib.Algebra.Ring.Equiv import Mathlib.Analysis.Analytic.Binomial import Mathlib.Analysis.Complex.Basic import Mathlib.Analysis.Complex.Norm import Mathlib.Analysis.Normed.Ring.Basic import Mathlib.Analysis.SpecificLimits.Normed import Mathlib.Data.Fin.VecNotation import Mathlib.Data.Finset.Card import Mathlib.Data.Finset.Insert import Mathlib.Data.Int.GCD import Mathlib.Data.Sym.Basic import Mathlib.Data.Sym.Card import Mathlib.LinearAlgebra.Dimension.Free import Mathlib.LinearAlgebra.Lagrange import Mathlib.NumberTheory.NumberField.InfinitePlace.TotallyRealComplex import Mathlib.NumberTheory.NumberField.Norm import Mathlib.RingTheory.Binomial import Mathlib.RingTheory.MvPolynomial.Symmetric.Defs import Mathlib.Tactic.ComputeDegree import Mathlib.Tactic.Linarith import Mathlib.Tactic.LinearCombination
Formal statement
section
open Finset Polynomial
namespace D1Bound5
theorem _root_.D1Bound5.coherent_two_three_forms_common_quadratic
{F : Type*} [Field F] (a R : Fin 4 → F) (z : F) (hab : a 0 ≠ a 1)
(h2 : -(a 0-a 1)*(a 0-a 2)*(a 1-a 2)*z +
a 0*(a 1-a 2)*R 0 - a 1*(a 0-a 2)*R 1 + a 2*(a 0-a 1)*R 2 = 0)
(h3 : -(a 0-a 1)*(a 0-a 3)*(a 1-a 3)*z +
a 0*(a 1-a 3)*R 0 - a 1*(a 0-a 3)*R 1 + a 3*(a 0-a 1)*R 3 = 0) :
∃ v w : F, ∀ i, z * (a i)^2 + v * a i + w = a i * R i := by sorry
end D1Bound5
end
Source
D1Bound5/CoherentThreeSimultaneous.lean, lines 20-47, SHA-256 ee201a480813e6432c988412c0b0b54c06b4815f872ad14ff04a828a0dbc941f. Project: https://github.com/tomislav-math/d1-bound5-lean