Remark after Lemma 1.1 — N(K₁ ∩ K₂, K₁ ∩ K₂) ⊆ N(K₁, K₂) ⊆ N(K₁ ∩ K₂, Q)

Initializing...

Remark after Lemma 1.1 — N(K₁ ∩ K₂, K₁ ∩ K₂) ⊆ N(K₁, K₂) ⊆ N(K₁ ∩ K₂, Q) · Prove2Me