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lean_workbook_plus_25399

Disproved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

⚠️ Retired — mistyped fractional exponent

The exponent ^(1 / 2) in the Lean statement below is natural-number division, not a real exponent, so it collapses to an integer power and the displayed radical is not what is being asserted. Do not import this node or use it as a dependency.

Let x−2y=t≥0. (1)\sqrt{x-2y}=t\ge 0.\ (1)x−2y​=t≥0. (1) Then the first equation gives y=12x3(3x+1−2xt). (2)y=\frac{1}{2x^3}(3x+1-2xt). \ (2)y=2x31​(3x+1−2xt). (2) From (1)(1)(1) and (2)(2)(2) we get x4−x3t2=3x+1−2xt. (3)x^4-x^3t^2=3x+1-2xt. \ (3)x4−x3t2=3x+1−2xt. (3) Substituting (2)(2)(2) into the second equation of the given system we get: x4+x3=x2(t2+1)(3−2t)+x(t2−2t+4)+1. (4)x^4+x^3=x^2(t^2+1)(3-2t)+x(t^2-2t+4)+1. \ (4)x4+x3=x2(t2+1)(3−2t)+x(t2−2t+4)+1. (4) Substituting x4x^4x4 from (3)(3)(3) into (4)(4)(4) we get x3=x2(3−2t)+x. (5)x^3=x^2(3-2t)+x. \ (5)x3=x2(3−2t)+x. (5) Multiplying (5)(5)(5) by xxx and substituting the resulting x4x^4x4 term into (3)(3)(3) we get x3(t−1)(t+3)=x2−(3−2t)x−1. (6)x^3(t-1)(t+3)=x^2-(3-2t)x-1. \ (6)x3(t−1)(t+3)=x2−(3−2t)x−1. (6) But the RHSRHSRHS of (6)(6)(6) is =0=0=0 because of (5).(5).(5). Therefore t=1.t=1.t=1. Now from (5)(5)(5) we get that x=1±52,x=\frac{1\pm\sqrt{5}}{2},x=21±5​​, and from (1)(1)(1) we get y=−1±54.y=\frac{-1\pm\sqrt{5}}{4}.y=4−1±5​​.

Why this node was retired

The posted statement is

theorem lean_workbook_plus_25399  (x y : ℝ)
  (h₀ : 0 ≤ x - 2 * y)
  (h₁ : (x - 2 * y)^(1 / 2) = x * y)
  (h₂ : x^4 + x^3 = x^2 * (x - 2 * y) + x * (x - 2 * y)^2 + 1) :
  x = (1 + Real.sqrt 5) / 2 ∧ y = (-1 + Real.sqrt 5) / 4 ∨ x = (1 - Real.sqrt 5) / 2 ∧ y = (-1 - Real.sqrt 5) / 4   :=  by sorry

A numeric-literal exponent carrying no type ascription is elaborated at type ℕ (via HPow ℝ ℕ ℝ, Monoid.npow), and natural-number division truncates. Each occurrence therefore collapses:

  • ^(1 / 2) → ^0, so the radical is 1 for every base

The recorded counterexample refutes the collapsed statement. It says nothing about the exercise displayed on this page, which is a different proposition.

What a faithful statement would require

Every fractional exponent must be given a real type, e.g. x ^ ((1 : ℝ) / 3) using Real.rpow, or be written with the intended root operation (Real.sqrt, or the signed real cube root where the radicand may be negative). Real powers also need their own domain hypotheses: rpow is only the intended root for a nonnegative base.

Proposed corrected statement

Recover the original two equations from the full source record, use Real.sqrt(x−2y), and prove the complete solution classification. The supplied derivation does not justify the different stored equations.

From the public Prove2Me statement audit (wamlat/prove2me-errors). That proposal is natural-language mathematics and is not Lean-verified; it is a specification for a corrected node, not a drop-in replacement.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_25399  (x y : ℝ)
  (h₀ : 0 ≤ x - 2 * y)
  (h₁ : (x - 2 * y)^(1 / 2) = x * y)
  (h₂ : x^4 + x^3 = x^2 * (x - 2 * y) + x * (x - 2 * y)^2 + 1) :
  x = (1 + Real.sqrt 5) / 2 ∧ y = (-1 + Real.sqrt 5) / 4 ∨ x = (1 - Real.sqrt 5) / 2 ∧ y = (-1 - Real.sqrt 5) / 4   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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