Middle tube minus relative interior splits into oriented halves
ProvedPolygonalArcMiddleTubeWithoutRelativeInteriorcrossing-consequencesgeometrypolygonal-arcs
For each middle segment, removing the polygonal arc's relative interior from the corresponding open tube leaves exactly the union of its positive and negative oriented half-tubes. Thus the two half-tubes give the two sides of the tube away from the arc.
Preamble
import Definitions.Def_PolygonalArcCollarLocalSideData open Classical noncomputable section
Formal statement
lemma PolygonalArcMiddleTubeWithoutRelativeInterior
(γ : PolygonalArc) {η : ℝ}
(controlRadii : PolygonalArcCollarControlRadii γ η)
(middleSegments : PolygonalArcCollarMiddleSegmentData γ controlRadii)
(forbiddenMargins :
PolygonalArcCollarMiddleForbiddenMargins γ controlRadii middleSegments)
(orientedTubes :
PolygonalArcCollarOrientedSeparatedTubeData γ controlRadii middleSegments
forbiddenMargins)
(vertexLocalPieces :
PolygonalArcCollarVertexLocalPieceData γ controlRadii middleSegments
forbiddenMargins orientedTubes.toPolygonalArcCollarSeparatedTubeData)
(localSideData :
PolygonalArcCollarLocalSideData γ controlRadii middleSegments
forbiddenMargins orientedTubes vertexLocalPieces)
(j : ℕ) (hj : j + 1 < γ.vertices.length) :
orientedTubes.toPolygonalArcCollarSeparatedTubeData.tube j hj \ γ.relativeInterior =
orientedTubes.toPolygonalArcCollarSeparatedTubeData.leftHalf j hj ∪
orientedTubes.toPolygonalArcCollarSeparatedTubeData.rightHalf j hj := by sorrySource