lean_workbook_plus_5353

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Let $a,b$ be positive real numbers such that $\frac{1}{a}+\frac{1}{b}=1.$ Prove that $4ab+\frac{3}{a+b}\leq \frac{35}{4}+a^2+b^2$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_5353 (a b : ℝ) (ha : 0 < a) (hb : 0 < b) (hab : 1 / a + 1 / b = 1) : 4 * a * b + 3 / (a + b) ≤ 35 / 4 + a ^ 2 + b ^ 2   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook

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