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Eq. (50), p. 791 — σ(λ)=qTv+βλ+o(1)\sigma(\lambda)=q^{\mathsf T}v+\beta\lambda+o(1)σ(λ)=qTv+βλ+o(1) as λ→∞\lambda\to\inftyλ→∞

Proved
RobustMDP.EntropyInner.dualFn_at_top

by mikedeng1 · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

asymptoticslog-sum-expp2o-batch-p100bp2o-gran-per-chapterp2o-plan-paperp2o-v1

Let q∈Δnq\in\Delta_nq∈Δn​ with q(j)>0q(j)>0q(j)>0 for all jjj, let β>0\beta>0β>0 and v∈Rnv\in\mathbb R^nv∈Rn, and let σ\sigmaσ be the dual function (47). Then

σ(λ)=qTv+βλ+o(1)(λ→∞),\sigma(\lambda)=q^{\mathsf T}v+\beta\lambda+o(1)\qquad(\lambda\to\infty),σ(λ)=qTv+βλ+o(1)(λ→∞),

that is, σ(λ)−(qTv+βλ)→0\sigma(\lambda)-(q^{\mathsf T}v+\beta\lambda)\to 0σ(λ)−(qTv+βλ)→0.

Together with the lower bound in (48), this says the affine function qTv+βλq^{\mathsf T}v+\beta\lambdaqTv+βλ is the asymptote of σ\sigmaσ at infinity.

Preamble
import Mathlib
import Definitions.Def_RobustMDP_EntropyInner_dualFunction
open Filter Topology
Formal statement
namespace RobustMDP.EntropyInner

/-- Eq. (50) (Nilim–El Ghaoui 2005, §6.3, p. 791; proof in Appendix C, p. 797). For `q ∈ Δₙ` with
`q > 0` and `β > 0`, as `λ → ∞`, `σ(λ) = qᵀv + βλ + o(1)`. -/
theorem dualFn_at_top {n : ℕ} (q v : Fin n → ℝ) (β : ℝ)
    (hq : q ∈ stdSimplex ℝ (Fin n)) (hq_pos : ∀ j, 0 < q j) (hβ : 0 < β) :
    Tendsto (fun lam => dualFn q v β lam - ((∑ j, q j * v j) + β * lam)) atTop (𝓝 0) := by sorry

end RobustMDP.EntropyInner
Source
Nilim and El Ghaoui, Robust Control of Markov Decision Processes with Uncertain Transition Matrices, Oper. Res. 53 (2005), p. 791, §6.3, Eq. (50); proof in Appendix C, p. 797
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. Let n∈Nn \in \mathbb{N}n∈N, let q,v∈Rnq, v \in \mathbb{R}^nq,v∈Rn and let β∈R\beta \in \mathbb{R}β∈R. Assume:

  • qqq lies in the probability simplex (qj≥0q_j \ge 0qj​≥0, ∑jqj=1\sum_j q_j = 1∑j​qj​=1);
  • qj>0q_j > 0qj​>0 for every jjj;
  • β>0\beta > 0β>0.

Notation. The dual function is

σ(λ)=λlog⁡ ⁣(∑jqjevj/λ)+βλ.\sigma(\lambda) = \lambda \log\!\Big(\sum_j q_j e^{v_j/\lambda}\Big) + \beta\lambda .σ(λ)=λlog(j∑​qj​evj​/λ)+βλ.

Conclusion. As λ→+∞\lambda \to +\inftyλ→+∞,

σ(λ)−(∑jqjvj+βλ)  ⟶  0.\sigma(\lambda) - \Big(\sum_j q_j v_j + \beta\lambda\Big) \;\longrightarrow\; 0 .σ(λ)−(j∑​qj​vj​+βλ)⟶0.

Equivalently, σ(λ)=∑jqjvj+βλ+o(1)\sigma(\lambda) = \sum_j q_j v_j + \beta\lambda + o(1)σ(λ)=∑j​qj​vj​+βλ+o(1).

Degenerate cases.

  • n=0n = 0n=0: excluded by the simplex hypothesis.
  • n=1n = 1n=1, or vvv constant: the difference is identically 000 for λ>0\lambda > 0λ>0.
  • β\betaβ: it cancels from the difference, so the hypothesis β>0\beta > 0β>0 plays no visible role.
  • Other values of λ\lambdaλ: only the behaviour for large positive λ\lambdaλ is asserted.
Human review
  • Endorsed by Shuze Chen · Sep 27, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Sep 27, 2026

    Confirmed by the mission captain (proposal self-audit).

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