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N=3N=3N=3: the 9×99\times99×9 matrix DDD with h=12h=\tfrac12h=21​, q=14q=\tfrac14q=41​

Proved
HardyFiveAxioms.qutrit_D_matrix

by Lucas · Oct 3, 2026 · Mathlib 0df444a (Lean v4.33.1)

linear-algebramathematical-physicsquantum-foundationsquantum-information

For N=3N=3N=3, order the fiducial projectors (26)–(27) as

1, 2, 3, 12x, 12y, 13x, 13y, 23x, 23y.1,\ 2,\ 3,\ 12x,\ 12y,\ 13x,\ 13y,\ 23x,\ 23y .1, 2, 3, 12x, 12y, 13x, 13y, 23x, 23y.

Then the matrix Dij=tr(P^iP^j)D_{ij}=\mathrm{tr}(\hat P_i\hat P_j)Dij​=tr(P^i​P^j​) is

D=(100hhhh00010hh00hh00100hhhhhh01hqqqqhh0h1qqqqh0hqq1hqqh0hqqh1qq0hhqqqq1h0hhqqqqh1),h=12, q=14.D=\begin{pmatrix} 1&0&0&h&h&h&h&0&0\\ 0&1&0&h&h&0&0&h&h\\ 0&0&1&0&0&h&h&h&h\\ h&h&0&1&h&q&q&q&q\\ h&h&0&h&1&q&q&q&q\\ h&0&h&q&q&1&h&q&q\\ h&0&h&q&q&h&1&q&q\\ 0&h&h&q&q&q&q&1&h\\ 0&h&h&q&q&q&q&h&1 \end{pmatrix},\qquad h=\tfrac12,\ q=\tfrac14 .D=​100hhhh00​010hh00hh​00100hhhh​hh01hqqqq​hh0h1qqqq​h0hqq1hqq​h0hqqh1qq​0hhqqqq1h​0hhqqqqh1​​,h=21​, q=41​.

In Section 8.7 Hardy derives this matrix from the axioms and states that "the projection operators which give rise to this DDD are, up to arbitrary choices in phase, those in equations (26) and (27)". This milestone checks that statement.

Formalization Note Indices are 000-based. The equality is entrywise in C\mathbb CC.

Preamble
import Mathlib
import Definitions.Def_hardy2001_projectors
Formal statement
namespace HardyFiveAxioms

/-- Hardy 2001, Section 8.7: for `N = 3` with fiducial order
`1, 2, 3, 12x, 12y, 13x, 13y, 23x, 23y`, the matrix `Dᵢⱼ = tr(P̂ᵢP̂ⱼ)` of the projectors
(26)–(27) has the stated form with `h = 1/2` and `q = 1/4`. -/
theorem qutrit_D_matrix :
    let P : Fin 9 → Matrix (Fin 3) (Fin 3) ℂ :=
      ![proj (ket 0), proj (ket 1), proj (ket 2),
        proj (ketX 0 1), proj (ketY 0 1), proj (ketX 0 2), proj (ketY 0 2),
        proj (ketX 1 2), proj (ketY 1 2)]
    let h : ℝ := 1 / 2
    let q : ℝ := 1 / 4
    let D : Matrix (Fin 9) (Fin 9) ℝ :=
      !![1, 0, 0, h, h, h, h, 0, 0;
         0, 1, 0, h, h, 0, 0, h, h;
         0, 0, 1, 0, 0, h, h, h, h;
         h, h, 0, 1, h, q, q, q, q;
         h, h, 0, h, 1, q, q, q, q;
         h, 0, h, q, q, 1, h, q, q;
         h, 0, h, q, q, h, 1, q, q;
         0, h, h, q, q, q, q, 1, h;
         0, h, h, q, q, q, q, h, 1]
    ∀ i j : Fin 9, (P i * P j).trace = (D i j : ℂ) := by sorry

end HardyFiveAxioms
Source
L. Hardy, *Quantum Theory From Five Reasonable Axioms*, arXiv:quant-ph/0101012v4 (2001), https://arxiv.org/abs/quant-ph/0101012, pp. 22–23, Section 8.7 (the 9×99\times99×9 matrix DDD with h=1/2h=1/2h=1/2, q=1/4q=1/4q=1/4)
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement below, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor, so it may share the drafter's blind spots. Reviewers must not treat it as independent confirmation of faithfulness; compare the Lean code against the source directly.

Let e0,e1,e2e_0,e_1,e_2e0​,e1​,e2​ be the standard basis of C3\mathbb C^3C3 and let proj(v)\mathrm{proj}(v)proj(v) be the 3×33\times33×3 matrix with entries vjvk‾v_j\overline{v_k}vj​vk​​. Define nine matrices P0,…,P8P_0,\dots,P_8P0​,…,P8​ as proj\mathrm{proj}proj of, in order: e0e_0e0​, e1e_1e1​, e2e_2e2​, 12(e0+e1)\tfrac1{\sqrt2}(e_0+e_1)2​1​(e0​+e1​), 12(e0+ie1)\tfrac1{\sqrt2}(e_0+ie_1)2​1​(e0​+ie1​), 12(e0+e2)\tfrac1{\sqrt2}(e_0+e_2)2​1​(e0​+e2​), 12(e0+ie2)\tfrac1{\sqrt2}(e_0+ie_2)2​1​(e0​+ie2​), 12(e1+e2)\tfrac1{\sqrt2}(e_1+e_2)2​1​(e1​+e2​), 12(e1+ie2)\tfrac1{\sqrt2}(e_1+ie_2)2​1​(e1​+ie2​). With h=12h=\tfrac12h=21​ and q=14q=\tfrac14q=41​, let DDD be the real 9×99\times99×9 matrix with rows

  • (1,0,0,h,h,h,h,0,0)(1,0,0,h,h,h,h,0,0)(1,0,0,h,h,h,h,0,0)
  • (0,1,0,h,h,0,0,h,h)(0,1,0,h,h,0,0,h,h)(0,1,0,h,h,0,0,h,h)
  • (0,0,1,0,0,h,h,h,h)(0,0,1,0,0,h,h,h,h)(0,0,1,0,0,h,h,h,h)
  • (h,h,0,1,h,q,q,q,q)(h,h,0,1,h,q,q,q,q)(h,h,0,1,h,q,q,q,q)
  • (h,h,0,h,1,q,q,q,q)(h,h,0,h,1,q,q,q,q)(h,h,0,h,1,q,q,q,q)
  • (h,0,h,q,q,1,h,q,q)(h,0,h,q,q,1,h,q,q)(h,0,h,q,q,1,h,q,q)
  • (h,0,h,q,q,h,1,q,q)(h,0,h,q,q,h,1,q,q)(h,0,h,q,q,h,1,q,q)
  • (0,h,h,q,q,q,q,1,h)(0,h,h,q,q,q,q,1,h)(0,h,h,q,q,q,q,1,h)
  • (0,h,h,q,q,q,q,h,1)(0,h,h,q,q,q,q,h,1)(0,h,h,q,q,q,q,h,1).

Then tr(PiPj)=Dij\mathrm{tr}(P_iP_j)=D_{ij}tr(Pi​Pj​)=Dij​, viewed in C\mathbb CC, for all i,j∈{0,…,8}i,j\in\{0,\dots,8\}i,j∈{0,…,8}.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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