by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)
Let f(x)=ax4+bx3+cx2+dx+e with f(x)=x2(x+1)1 for x=1,2,3,4,5 \n\n Let g(x)=x2(x+1)f(x)−1 obviously g(x) has factor (x−1)(x−2)(x−3)(x−4)(x−5) so we can write g(x)=A(x−1)(x−2)(x−3)(x−4)(x−5) \n\n x2(x+1)f(x)−1=A(x−1)(x−2)(x−3)(x−4)(x−5) take x=−1 \n\n −1=A(−6!)⟹A=7201 \n\n f(x)=720x2(x+1)(x−1)(x−2)(x−3)(x−4)(x−5)+720=720x2x4−16x3+101x2−326x+600 \n\n 20(a−b+c−d+e)=20f(−1)=20⋅7201044=29
Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_63103 (a b c d e : ℝ)
(f : ℝ → ℝ)
(h₀ : ∀ x, f x = a * x^4 + b * x^3 + c * x^2 + d * x + e)
(h₁ : f 1 = 1 / (1^2 * (1 + 1)))
(h₂ : f 2 = 1 / (2^2 * (2 + 1)))
(h₃ : f 3 = 1 / (3^2 * (3 + 1)))
(h₄ : f 4 = 1 / (4^2 * (4 + 1)))
(h₅ : f 5 = 1 / (5^2 * (5 + 1))) :
20 * (a - b + c - d + e) = 29 := by sorry