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Appendix B.2.b: Bell-measurement error and repeater yield, Eq.(B3)

Proved
QAlgorithms.Papers.Independent.Gap48.P25.bellErrorRate

by Goku · Oct 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let R2≥0R_2\ge0R2​≥0 be the mean-cycle detection rate and let F∈[0,1]F\in[0,1]F∈[0,1] be the Bell measurement fidelity. The desired Bell state has probability FFF and each other Bell state has probability (1−F)/3(1-F)/3(1−F)/3. One wrong Bell state preserves the bit correlation and the other two reverse it. The error and assigned signed one-way perfect-EC toy yield are

ε=23(1−F),K2=R2[1−2h(ε)],K2+=R2max⁡{1−2h(ε),0}.\varepsilon={2\over3}(1-F),\qquad K_2=R_2[1-2h(\varepsilon)],\qquad K_2^+=R_2\max\{1-2h(\varepsilon),0\}.ε=32​(1−F),K2​=R2​[1−2h(ε)],K2+​=R2​max{1−2h(ε),0}.

There is a unique q∗∈(0,1/2)q_*\in(0,1/2)q∗​∈(0,1/2) with h(q∗)=1/2h(q_*)=1/2h(q∗​)=1/2. In the useful branch F≥1/4F\ge1/4F≥1/4, K2>0K_2>0K2​>0 exactly when R2>0R_2>0R2​>0 and F>1−3q∗/2F>1-3q_*/2F>1−3q∗​/2. This gives the source's threshold implicitly, without treating its approximate 83.5 percent decimal as exact.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Gap48_P25
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Gap48.P25

open scoped BigOperators ComplexConjugate

open Filter

open QAlgorithms.Papers.Independent.Claimed50.P08 (classicalEntropy)

/-- Eq.(B3), PDF p.47: computed Bell error and assigned mean-cycle yield.
The approximate decimal threshold is replaced by its implicit entropy definition. -/
theorem bellErrorRate (R F : ℝ) (hR : 0 ≤ R) (hF : F ∈ Set.Icc (0 : ℝ) 1) :
    (∀ i, 0 ≤ bellLaw F i) ∧ (∑ i : Fin 4, bellLaw F i) = 1 ∧
    bellError F = (2/3)*(1-F) ∧
    repeaterKey R F = R*(1-2*QAlgorithms.binEntropy2 ((2/3)*(1-F))) ∧
    max (repeaterKey R F) 0 = R*max (1-2*QAlgorithms.binEntropy2 ((2/3)*(1-F))) 0 ∧
    ∃ q : ℝ, 0 < q ∧ q < 1/2 ∧ QAlgorithms.binEntropy2 q = 1/2 ∧
      (∀ z : ℝ, z ∈ Set.Icc (0 : ℝ) (1/2) → (QAlgorithms.binEntropy2 z = 1/2 ↔ z = q)) ∧
      (1/4 ≤ F → (0 < repeaterKey R F ↔ 0 < R ∧ 1-(3/2)*q < F)) := by sorry

end QAlgorithms.Papers.Independent.Gap48.P25

end
Source
The Security of Practical Quantum Key Distribution, arXiv:0802.4155v3, PDF p. 47, Appendix B.2.b: Bell-measurement error and repeater yield, Eq.(B3)
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every real R≥0R\ge0R≥0 and F∈[0,1]F\in[0,1]F∈[0,1], define PF(0)=FP_F(0)=FPF​(0)=F and PF(i)=(1−F)/3P_F(i)=(1-F)/3PF​(i)=(1−F)/3 for i=1,2,3i=1,2,3i=1,2,3, let eF=∑i=23PF(i)e_F=\sum_{i=2}^{3}P_F(i)eF​=∑i=23​PF​(i), and let H(q)=[−qlog⁡q−(1−q)log⁡(1−q)]/log⁡2H(q)=[-q\log q-(1-q)\log(1-q)]/\log2H(q)=[−qlogq−(1−q)log(1−q)]/log2, with 0log⁡0=00\log0=00log0=0. Define K(R,F)=R(1−H(eF)−H(eF))K(R,F)=R(1-H(e_F)-H(e_F))K(R,F)=R(1−H(eF​)−H(eF​)). Then all four PF(i)P_F(i)PF​(i) are nonnegative, their sum is 111, and

eF=23(1−F),K(R,F)=R(1−2H(23(1−F))),max⁡{K(R,F),0}=Rmax⁡{1−2H(23(1−F)),0}.e_F=\frac23(1-F),\qquad K(R,F)=R\left(1-2H\left(\frac23(1-F)\right)\right),\qquad \max\{K(R,F),0\}=R\max\left\{1-2H\left(\frac23(1-F)\right),0\right\}.eF​=32​(1−F),K(R,F)=R(1−2H(32​(1−F))),max{K(R,F),0}=Rmax{1−2H(32​(1−F)),0}.

There exists a real qqq with 0<q<1/20<q<1/20<q<1/2 and H(q)=1/2H(q)=1/2H(q)=1/2, such that for every z∈[0,1/2]z\in[0,1/2]z∈[0,1/2], H(z)=1/2H(z)=1/2H(z)=1/2 if and only if z=qz=qz=q, and, if F≥1/4F\ge1/4F≥1/4,

K(R,F)>0  ⟺  R>0 and F>1−32q.K(R,F)>0\iff R>0\ \text{and}\ F>1-\frac32q.K(R,F)>0⟺R>0 and F>1−23​q.

The assumptions permit R=0R=0R=0 and F=0F=0F=0 or 111; the final positivity equivalence is asserted only under F≥1/4F\ge1/4F≥1/4.

Human review
  • Endorsed by Shuze Chen · Oct 21, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Goku · Oct 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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