Triangulation extension of a finite planar drawing
ProvedWilliamsonShmoys.planar_triangulation_extension__p2m_9f0d58b7_b6f9_47f0_b3be_8c258362d568_a2approximation-algorithmsplanar-graphstreewidth
For any graph on a finite linearly ordered vertex type with at least three vertices, if it has a drawing satisfying the given continuous-arc, injectivity, vertex-avoidance, and edge-intersection conditions, then it has a planar supergraph on the same vertex type with exactly 3|V|−6 edges. The proof proceeds by obtaining a finite plane embedding, connecting components as needed, and triangulating faces; Euler's formula supplies the exact count. The argument must preserve all vertices, including isolated ones.
Preamble
import Definitions.Def_WilliamsonShmoys_PlanarDrawingOn import Mathlib set_option autoImplicit false open WilliamsonShmoys
Formal statement
theorem WilliamsonShmoys.planar_triangulation_extension__p2m_9f0d58b7_b6f9_47f0_b3be_8c258362d568_a2
{V : Type} [Fintype V] [LinearOrder V]
(H : SimpleGraph V) (hcard : 3 ≤ Fintype.card V)
(hplanar : HasPlanarDrawingOn H) :
∃ K : SimpleGraph V, H ≤ K ∧ HasPlanarDrawingOn K ∧
3 * Fintype.card V = K.edgeSet.ncard + 6 := by sorrySource
David P. Williamson and David B. Shmoys, The Design of Approximation Algorithms, Cambridge University Press, 2011, author electronic manuscript, Section 10.2, proof of Theorem 10.11, pp. 270-272. https://doi.org/10.1017/CBO9780511921735. Bounded tree-width of the pieces: Robertson–Seymour (planar graphs of radius r have tree-width at most 3r+1) / Bodlaender (k-outerplanar graphs have tree-width at most 3k-1).