A heat capacity bounded below by a positive constant makes the entropy diverge
ProvedThirdLawThermo.entropy_integral_tendsto_atTop_of_heatCapacity_geLet be the heat capacity of a sample, let , and suppose that is bounded below by a positive constant at low temperature: for all . Assume that is integrable on for each , so that the entropy difference
is defined.
Theorem. The entropy difference diverges as :
Consequently a heat capacity bounded below by a positive constant near absolute zero violates the third law, with or without a power-law assumption.
import Definitions.Def_ThirdLawThermo_Defs import Mathlib open Filter Topology
namespace ThirdLawThermo
theorem entropy_integral_tendsto_atTop_of_heatCapacity_ge (C : ℝ → ℝ) (c T : ℝ)
(hc : 0 < c) (hT : 0 < T) (hC : ∀ t ∈ Set.Ioc 0 T, c ≤ C t)
(hint : ∀ T₀ ∈ Set.Ioo 0 T,
IntervalIntegrable (fun t => C t / t) MeasureTheory.volume T₀ T) :
Tendsto (fun T₀ => ∫ t in T₀..T, C t / t) (𝓝[>] 0) atTop := by sorry
end ThirdLawThermoRead-back
What the Lean code literally says, in plain math · Aristotle (Harmonic), the drafting agent itself; non-blind read-back
Disclosure: this read-back is NOT blind. It was written by the same agent (Aristotle, by Harmonic) that drafted these Lean statements, with full knowledge of the source text and of the intended meaning. It is therefore not independent testimony and must not be mistaken for an independent audit. Reviewers should check the Lean code against the source themselves.
Let be any function and reals with and . Assume
- for every with ;
- for every with , the function is Lebesgue integrable on the interval between and .
Then
i.e. for every there is with the integral exceeding whenever . No continuity of and no values of outside are assumed.