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Partial sums ∑k≤nτ(k)=O(n13/2+ε)\sum_{k\le n}\tau(k)=O(n^{13/2+\varepsilon})∑k≤n​τ(k)=O(n13/2+ε)

Proved
RamanujanPetersson.tau_partial_sum_isBigO

by Lucas · Oct 12, 2026 · Mathlib 0df444a (Lean v4.33.1)

modular-formsnumber-theory

For every ε>0\varepsilon>0ε>0,

∑k=1nτ(k)=O ⁣(n13/2+ε)(n→∞).\sum_{k=1}^{n}\tau(k)=O\!\left(n^{13/2+\varepsilon}\right)\qquad(n\to\infty).k=1∑n​τ(k)=O(n13/2+ε)(n→∞).

The source presents this as the general estimate behind the absolute convergence of the Ramanujan LLL-series.

Formalization Note τ\tauτ is RamanujanPetersson.tau, the nnn-th coefficient of Mathlib's qqq-expansion (period 111) of ModularForm.discriminant, valued in C\mathbb CC.

Preamble
import Mathlib
import Definitions.Def_RamanujanPetersson_tau

open UpperHalfPlane Filter Asymptotics MatrixGroups
open scoped Real
Formal statement
namespace RamanujanPetersson

theorem tau_partial_sum_isBigO (ε : ℝ) (hε : 0 < ε) :
    (fun n : ℕ => ∑ k ∈ Finset.Icc 1 n, tau k) =O[atTop]
      fun n : ℕ => (n : ℝ) ^ ((13 : ℝ) / 2 + ε) := by sorry

end RamanujanPetersson
Source
Wikipedia, "Ramanujan–Petersson conjecture", https://en.wikipedia.org/w/index.php?title=Ramanujan%E2%80%93Petersson_conjecture&oldid=1369029052 (PDF snapshot supplied by the proposer, 9 pp.), section "Ramanujan L-function", display "From general estimation for tau function ∑k=1nτ(k)=O(n13/2+ϵ)\sum_{k=1}^n\tau(k)=O(n^{13/2+\epsilon})∑k=1n​τ(k)=O(n13/2+ϵ)"
Human review
  • Endorsed by Shuze Chen · Oct 13, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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