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Extension reconstructs a reduced bispace

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QAlgorithms.Papers.Independent.Intakethird100.P93.lemma_2_11

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let t:G→Ht:G\to Ht:G→H be a topological crossed module, with continuous action α:H→Aut⁡(G)\alpha:H\to\operatorname{Aut}(G)α:H→Aut(G). Thus t(α(h)g)=ht(g)h−1t(\alpha(h)g)=ht(g)h^{-1}t(α(h)g)=ht(g)h−1 and α(t(g))k=gkg−1\alpha(t(g))k=gkg^{-1}α(t(g))k=gkg−1. Put G1=ker⁡tG_1=\ker tG1​=kert and give both G/G1G/G_1G/G1​ and H/t(G)H/t(G)H/t(G) their quotient topologies. Assume their quotient projections admit continuous local sections. All actions, structure maps and isomorphisms below are continuous, all principal bundles are locally trivial, and a bispace has a nonempty principal homogeneous underlying right space.

Let G0≤GG_0\le GG0​≤G and H0≤HH_0\le HH0​≤H be a crossed submodule: t(G0)⊆H0t(G_0)\subseteq H_0t(G0​)⊆H0​ and α(H0)\alpha(H_0)α(H0​) preserves G0G_0G0​ setwise. Let X0⊆XX_0\subseteq XX0​⊆X be a reduction of an (H,G)(H,G)(H,G)-bispace, meaning a single nonempty G0G_0G0​-orbit with ψ(X0)⊆H0\psi(X_0)\subseteq H_0ψ(X0​)⊆H0​. Form X0(G)=X0×G0GX_0(G)=X_0\times_{G_0}GX0​(G)=X0​×G0​​G using (x,g)k=(xk,k−1g)(x,g)k=(xk,k^{-1}g)(x,g)k=(xk,k−1g). Then

X0(G)⟶X,[x,g]⟼xgX_0(G)\longrightarrow X,\qquad [x,g]\longmapsto xgX0​(G)⟶X,[x,g]⟼xg

is a right equivariant homeomorphism preserving ψ([x,g])=ψ(x)t(g)\psi([x,g])=\psi(x)t(g)ψ([x,g])=ψ(x)t(g). This identifies extension of the given reduction with the original bispace by the canonical map.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P93
Formal statement
namespace QAlgorithms.Papers.Independent.Intakethird100.P93

universe u

variable {G H : Type u} [Group G] [TopologicalSpace G] [IsTopologicalGroup G]
  [Group H] [TopologicalSpace H] [IsTopologicalGroup H]

variable (C : CrossedModule G H)

/-- Lemma 2.11, PDF p.7: the canonical map [x,g]↦xg is a homeomorphism,
right equivariant and structure preserving. The equations on representatives also
specify the descended action and structure map without assuming their existence. -/
theorem lemma_2_11 {X : Type u} [TopologicalSpace X] (B : Bispace C X)
    (K : Subgroup G) (L : Subgroup H) (S : Set X)
    (hsub : IsCrossedSubmodule C K L) (hred : IsReduction C B K L S) :
    ∃ e : ExtensionSpace B.right K S ≃ₜ X,
      (∀ x g, e (extensionClass B.right K S x g) = B.right.act x.val g) ∧
      (∀ x g k, e (extensionClass B.right K S x (g * k)) =
        B.right.act (e (extensionClass B.right K S x g)) k) ∧
      (∀ x g, B.psi (e (extensionClass B.right K S x g)) =
        B.psi x.val * C.t g) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P93
Source
On the existence of bibundles, arXiv:1102.4388v2, PDF p. 7, Lemma 2.11
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let G,HG,HG,H be topological groups, and let CCC consist of a continuous homomorphism t:G→Ht:G\to Ht:G→H and a homomorphism α:H→Aut⁡(G)\alpha:H\to\operatorname{Aut}(G)α:H→Aut(G) whose evaluation is continuous, satisfying t(αh(g))=h t(g) h−1t(\alpha_h(g))=h\,t(g)\,h^{-1}t(αh​(g))=ht(g)h−1 and αt(g)(k)=gkg−1\alpha_{t(g)}(k)=gkg^{-1}αt(g)​(k)=gkg−1 for all h∈Hh\in Hh∈H and g,k∈Gg,k\in Gg,k∈G. Assume the quotient maps G→G/ker⁡tG\to G/\ker tG→G/kert and H→H/t(G)H\to H/t(G)H→H/t(G) have continuous right inverses on open neighborhoods of every target point. Let XXX be a topological space with a continuous right GGG-action x⋅gx\cdot gx⋅g satisfying the identity and action laws, such that XXX is nonempty and every orbit map g↦x⋅gg\mapsto x\cdot gg↦x⋅g is a homeomorphism G→XG\to XG→X, and let ψ:X→H\psi:X\to Hψ:X→H be continuous with ψ(x⋅g)=ψ(x)t(g)\psi(x\cdot g)=\psi(x)t(g)ψ(x⋅g)=ψ(x)t(g). Let K≤GK\le GK≤G, L≤HL\le HL≤H, and S⊆XS\subseteq XS⊆X. Assume t(k)∈Lt(k)\in Lt(k)∈L for every k∈Kk\in Kk∈K, and αh(k)∈K\alpha_h(k)\in Kαh​(k)∈K for every h∈Lh\in Lh∈L and k∈Kk\in Kk∈K. Assume also that there exists a∈Xa\in Xa∈X with S={a⋅k:k∈K}S=\{a\cdot k:k\in K\}S={a⋅k:k∈K}, and that ψ(x)∈L\psi(x)\in Lψ(x)∈L for every x∈Sx\in Sx∈S; in particular, these hypotheses require SSS to be nonempty. Let EEE be the quotient of S×GS\times GS×G, with SSS carrying its subspace topology, obtained by identifying (x,g)(x,g)(x,g) with (x⋅k,k−1g)(x\cdot k,k^{-1}g)(x⋅k,k−1g) whenever k∈Kk\in Kk∈K, where the first coordinates are regarded as points of SSS. Then there exists a homeomorphism e:E→Xe:E\to Xe:E→X such that, for every x∈Sx\in Sx∈S and g,k∈Gg,k\in Gg,k∈G,

e([x,g])=x⋅g,e([x,gk])=e([x,g])⋅k,ψ(e([x,g]))=ψ(x)t(g).e([x,g])=x\cdot g,\qquad e([x,gk])=e([x,g])\cdot k,\qquad \psi(e([x,g]))=\psi(x)t(g).e([x,g])=x⋅g,e([x,gk])=e([x,g])⋅k,ψ(e([x,g]))=ψ(x)t(g).
Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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