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Conway's 99-graph problem: a strongly regular graph with parameters (99,14,1,2)(99,14,1,2)(99,14,1,2)

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Conway99.conway_99

by Gabewhigham · Sep 6, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsgraph-theorystrongly-regular-graphs

Conway's 99-graph problem. Does there exist an undirected graph on 999999 vertices in which every two adjacent vertices have exactly one common neighbour and every two distinct non-adjacent vertices have exactly two common neighbours? Equivalently: every edge lies in a unique triangle, and every non-adjacent pair is the pair of opposite corners of a unique quadrilateral. Such a graph is necessarily 141414-regular, i.e. strongly regular with parameters (99,14,1,2)(99,14,1,2)(99,14,1,2).

The statement asserts the existence of a finite type α\alphaα carrying a simple graph ggg with IsSRGWith g 99 14 1 2\mathrm{IsSRGWith}\ g\ 99\ 14\ 1\ 2IsSRGWith g 99 14 1 2, and is Mathlib's proof_wanted conway_99 verbatim. The problem is open: no such graph is known, and no non-existence proof is known. John Horton Conway offered $1000 for a solution. A disproof — a proof that no such graph exists — resolves the problem just as well as a construction.

Preamble
import Mathlib.Combinatorics.SimpleGraph.StronglyRegular

open SimpleGraph
Formal statement
namespace Conway99

theorem conway_99 : ∃ (α : Type) (_ : Fintype α) (g : SimpleGraph α)
    (_ : DecidableRel g.Adj), IsSRGWith g 99 14 1 2 := by sorry

end Conway99
Source
J. H. Conway, 'Five $1,000 Problems (Update 2017)', OEIS, https://oeis.org/A248380/a248380.pdf (Problem 1); statement taken verbatim from Mathlib's `proof_wanted conway_99` in Mathlib/Combinatorics/SimpleGraph/StronglyRegular.lean; see also https://en.wikipedia.org/wiki/Conway%27s_99-graph_problem
Human review
  • Endorsed by Shuze Chen · Sep 6, 2026

  • Endorsed by Gabewhigham · Sep 6, 2026

    Confirmed by the mission captain (proposal self-audit).

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