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Signatures of real, quaternionic and K=N3K=N^3K=N3 theories

Proved
HardyFiveAxioms.signature_real_quaternionic_cubic

by Lucas · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsmathematical-physicsquantum-foundations

For every N∈NN\in\mathbb NN∈N:

  1. the real-Hilbert-space signature (1,1,0,… )(1,1,0,\dots)(1,1,0,…) gives K=N+(N2)=12N(N+1)K=N+\binom N2=\tfrac12N(N+1)K=N+(2N​)=21​N(N+1);
  2. the quaternionic signature (1,4,0,… )(1,4,0,\dots)(1,4,0,…) gives K=N+4(N2)=2N2−NK=N+4\binom N2=2N^2-NK=N+4(2N​)=2N2−N;
  3. the signature (1,6,6,0,… )(1,6,6,0,\dots)(1,6,6,0,…) gives K=N+6(N2)+6(N3)=N3K=N+6\binom N2+6\binom N3=N^3K=N+6(2N​)+6(3N​)=N3.

In Lean these read 2K(1,1)(N)=N(N+1)2K_{(1,1)}(N)=N(N+1)2K(1,1)​(N)=N(N+1), K(1,4)(N)+N=2N2K_{(1,4)}(N)+N=2N^2K(1,4)​(N)+N=2N2 and K(1,6,6)(N)=N3K_{(1,6,6)}(N)=N^3K(1,6,6)​(N)=N3.

Formalization Note The forms 2K=N(N+1)2K=N(N+1)2K=N(N+1) and K+N=2N2K+N=2N^2K+N=2N2 avoid natural-number division and subtraction.

Preamble
import Mathlib
import Definitions.Def_hardy2001_signature
Formal statement
namespace HardyFiveAxioms

/-- Hardy 2001, Sections 5 and 8.1: the real-Hilbert-space signature `(1, 1, 0, …)` gives
`K = N(N+1)/2`, the quaternionic signature `(1, 4, 0, …)` gives `K = 2N² - N`, and the
signature `(1, 6, 6, 0, …)` gives `K = N³`. -/
theorem signature_real_quaternionic_cubic (N : ℕ) :
    2 * dofOfSignature [1, 1] N = N * (N + 1) ∧
      dofOfSignature [1, 4] N + N = 2 * N ^ 2 ∧
      dofOfSignature [1, 6, 6] N = N ^ 3 := by sorry

end HardyFiveAxioms
Source
L. Hardy, *Quantum Theory From Five Reasonable Axioms*, arXiv:quant-ph/0101012v4 (2001), https://arxiv.org/abs/quant-ph/0101012, p. 8, Section 5 (after Eq. (28)); p. 17, Section 8.1 (real and quaternionic Hilbert spaces, K=N3K=N^3K=N3)
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement below, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor, so it may share the drafter's blind spots. Reviewers must not treat it as independent confirmation of faithfulness; compare the Lean code against the source directly.

For every natural number NNN, all in N\mathbb NN:

  1. 2((N1)+(N2))=N(N+1)2\big(\binom N1+\binom N2\big)=N(N+1)2((1N​)+(2N​))=N(N+1);
  2. (N1)+4(N2)+N=2N2\binom N1+4\binom N2+N=2N^2(1N​)+4(2N​)+N=2N2;
  3. (N1)+6(N2)+6(N3)=N3\binom N1+6\binom N2+6\binom N3=N^3(1N​)+6(2N​)+6(3N​)=N3.

Here the left-hand sums are K[1,1](N)K_{[1,1]}(N)K[1,1]​(N), K[1,4](N)K_{[1,4]}(N)K[1,4]​(N) and K[1,6,6](N)K_{[1,6,6]}(N)K[1,6,6]​(N) for the signature function of hardy2001_signature.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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