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Lemma 8: the composed quantum correction has zero right derivative

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QAlgorithms.Papers.Independent.Intakethird100.P50.quantumCorrection_zero_rightDerivative

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let e≥2e\ge2e≥2 be an integer, c≥0c\ge0c≥0 a real constant and r>1r>1r>1. With hhh the binary entropy in bits, define

f1(e,η)=η2log⁡2(e−1)+ηlog⁡2e+h(η/2)+(1+η/2)h ⁣(η2+η).f_1(e,\eta)=\frac\eta2\log_2(e-1)+\eta\log_2e+h(\eta/2)+(1+\eta/2)h\!\left(\frac\eta{2+\eta}\right).f1​(e,η)=2η​log2​(e−1)+ηlog2​e+h(η/2)+(1+η/2)h(2+ηη​).

The composition has right derivative zero at the noise-free point:

ddp+f1(e,cpr)∣p=0=0.\left.\frac{d}{dp^+}f_1(e,cp^r)\right|_{p=0}=0.dp+d​f1​(e,cpr)​p=0​=0.

Only a physical right neighborhood of zero is relevant. The case c=0c=0c=0 is included as the constant-zero composition. The result explains the tangency of the capacity correction to coherent information.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P50
Formal statement
noncomputable section

open scoped BigOperators Matrix ComplexConjugate ComplexOrder

open Filter

namespace QAlgorithms.Papers.Independent.Intakethird100.P50

variable {A B E F : Type}

variable [Fintype A] [DecidableEq A] [Fintype B] [DecidableEq B]

variable [Fintype E] [DecidableEq E] [Fintype F] [DecidableEq F]

open QAlgorithms.Papers.Independent.Information100.P67
  (IsIsometry receiverChannel complementaryChannel maximumCoherentInformation
    dilationPower idealJoint)

open QAlgorithms.Papers.Independent.Information100.P80 (log2)

open QAlgorithms.Papers.Independent.Information100.P69 (diamond choi)

open QAlgorithms.Papers.Independent.Support50.P07 (fullTracePrivateCapacity)

open QAlgorithms.Papers.Independent.Frontier18.P17 (clock)

/-- Lemma 8, PDF p.9: right derivative on physical p≥0, including c=0.
Choi rank e≥2 is the domain of the displayed entropy correction. -/
theorem quantumCorrection_zero_rightDerivative (e : ℕ) (he : 2 ≤ e)
    (c r : ℝ) (hc : 0 ≤ c) (hr : 1 < r) :
    HasDerivWithinAt (fun p : ℝ => quantumCorrection e (c * p ^ r)) 0 (Set.Ici 0) 0 := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P50

end
Source
Quantum and private capacities of low-noise channels, arXiv:1705.04335v3, PDF p. 9, Lemma 8: the composed quantum correction has zero right derivative
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every natural number e≥2e\ge2e≥2 and real numbers c≥0c\ge0c≥0, r>1r>1r>1, define

qe(η)=η2log⁡2(e−1)+ηlog⁡2e+h2(η/2)+(1+η/2)h2 ⁣(η2+η),h2(x)=−xln⁡x−(1−x)ln⁡(1−x)ln⁡2.q_e(\eta)= \frac{\eta}{2}\log_2(e-1)+\eta\log_2e+ h_2(\eta/2)+(1+\eta/2)h_2\!\left(\frac{\eta}{2+\eta}\right), \qquad h_2(x)=\frac{-x\ln x-(1-x)\ln(1-x)}{\ln2}.qe​(η)=2η​log2​(e−1)+ηlog2​e+h2​(η/2)+(1+η/2)h2​(2+ηη​),h2​(x)=ln2−xlnx−(1−x)ln(1−x)​.

Then the function p↦qe(cpr)p\mapsto q_e(cp^r)p↦qe​(cpr) has derivative zero at p=0p=0p=0 within the set [0,∞)[0,\infty)[0,∞). Here prp^rpr is real exponentiation and log⁡2x=ln⁡x/ln⁡2\log_2x=\ln x/\ln2log2​x=lnx/ln2; the logarithms and divisions use their total real definitions, including ln⁡0=0\ln0=0ln0=0 and division by zero equal to zero. In particular, the function has value zero at p=0p=0p=0. The statement includes c=0c=0c=0, and concerns only the derivative within the nonnegative half-line.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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