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A sufficient integer linear system for the auxiliary function, from presentations whose degree in ω grows with T·a

Proved
FourExp.aux_linear_system_column

by carlok · Sep 30, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leanexponential-polynomialsnumber-theorytranscendence

Let x1,x2,y1,y2,ω,ω1∈Cx_1, x_2, y_1, y_2, \omega, \omega_1 \in \mathbb{C}x1​,x2​,y1​,y2​,ω,ω1​∈C and Q∈Z[X][Y]Q \in \mathbb{Z}[X][Y]Q∈Z[X][Y]. For integers qijkμνq_{ijk\mu\nu}qijkμν​ (i<Si < Si<S, j,k<Tj, k < Tj,k<T, μ<M\mu < Mμ<M, ν<deg⁡YQ\nu < \deg_Y Qν<degY​Q) put Fq(z)=∑i,j,k(∑μ,νqijkμν ωμω1ν)zie(jx1+kx2)zF_q(z) = \sum_{i,j,k}\big(\sum_{\mu,\nu} q_{ijk\mu\nu}\,\omega^{\mu}\omega_1^{\nu}\big) z^{i} e^{(jx_1 + kx_2)z}Fq​(z)=∑i,j,k​(∑μ,ν​qijkμν​ωμω1ν​)zie(jx1​+kx2​)z, and suppose that the derivatives of FqF_qFq​ have the reduced presentations in the conclusion of FourExp.exists_iteratedDeriv_reduced_presentation_column, with XXX-degrees at most M+c(1+m+S+Ta)M + c(1+m+S+Ta)M+c(1+m+S+Ta). Then there is κ1>0\kappa_1 > 0κ1​>0 such that for every large NNN, with

S=⌊N2/log⁡N⌋,T=2N,t1=⌊N/log⁡N⌋,t2=⌊Nlog⁡N⌋,S = \lfloor N^{2}/\sqrt{\log N}\rfloor,\quad T = 2N,\quad t_1 = \lfloor N/\sqrt{\log N}\rfloor,\quad t_2 = \lfloor N\sqrt{\log N}\rfloor,S=⌊N2/logN​⌋,T=2N,t1​=⌊N/logN​⌋,t2​=⌊NlogN​⌋,

there are an integer MMM with 0<M≤κ1S0 < M \le \kappa_1 S0<M≤κ1​S and an integer matrix BBB with RRR rows, 2R≤ST2Mdeg⁡YQ2R \le ST^{2}M\deg_Y Q2R≤ST2MdegY​Q, and entries at most eκ1N2log⁡Ne^{\kappa_1 N^{2}\sqrt{\log N}}eκ1​N2logN​, such that Bq=0Bq = 0Bq=0 implies Fq(m)(ay1+by2)=0F_q^{(m)}(ay_1 + by_2) = 0Fq(m)​(ay1​+by2​)=0 for all a<t1a < t_1a<t1​, b<t2b < t_2b<t2​, m<Sm < Sm<S.

This is the equation count of Lemme 4 of Waldschmidt (1973), and FourExp.aux_linear_system with the presentation as its only hypothesis; the conclusion is the same. In the four exponentials case the XXX-degrees are at most M+c(1+m+S)M + c(1+m+S)M+c(1+m+S). Here a<t1a < t_1a<t1​ gives Ta≤2Nt1≤2STa \le 2Nt_1 \le 2STa≤2Nt1​≤2S, so M=(5c+1)SM = (5c+1)SM=(5c+1)S in place of (3c+1)S(3c+1)S(3c+1)S still leaves at least twice as many unknowns as equations.

Preamble
import Mathlib
Formal statement
namespace FourExp

/-- The auxiliary linear system of Waldschmidt's argument, from a reduced presentation of the
derivatives whose `X`-degrees grow with `T a`.

Write `φ(P) = P(ω, ω₁)` for `P ∈ ℤ[X][Y]`, `S = ⌊N² / √(log N)⌋`, `t₁ = ⌊N / √(log N)⌋` and
`t₂ = ⌊N √(log N)⌋`. The unknowns are integers `q_{ijkμν}` with `i < S`, `j, k < 2N`, `μ < M`,
`ν < deg Q`, and `F_q(z) = ∑ (∑_{μ,ν} q_{ijkμν} ω^μ ω₁^ν) z^i e^((j x₁ + k x₂) z)`. The hypothesis
`hpres` is the conclusion of `FourExp.exists_iteratedDeriv_reduced_presentation_column`: the
derivatives have reduced presentations with `X`-degrees at most `M + c (1 + m + S + T a)`.

Then there are, for large `N`, an `M ≤ κ₁ S` and an integer system with at most half as many
equations as unknowns and coefficients at most `e^(κ₁ N² √(log N))`, whose solutions make
`F_q⁽ᵐ⁾(a y₁ + b y₂)` vanish for `a < t₁`, `b < t₂`, `m < S`. The conclusion is that of
`FourExp.aux_linear_system`. Since `a < t₁` gives `T a ≤ 2 N t₁ ≤ 2 S`, `M = (5 c + 1) S` leaves
room for the `X`-degrees. -/
theorem aux_linear_system_column
    (x₁ x₂ y₁ y₂ : ℂ) (ω ω₁ : ℂ) (Q : Polynomial (Polynomial ℤ))
    (hpres : ∃ c : ℕ, ∀ S T M a b m : ℕ, ∃ Λ : ℂ, Λ ≠ 0 ∧
      ‖Λ‖ ≤ (c : ℝ) ^ (c * (1 + m + S + T * (a + b))) ∧
      ∃ R : Fin S → Fin T → Fin T → Fin M → Fin Q.natDegree → Polynomial (Polynomial ℤ),
        (∀ i j k μ ν, (R i j k μ ν).natDegree < Q.natDegree) ∧
        (∀ i j k μ ν, ∑ r ∈ (R i j k μ ν).support, ∑ h ∈ ((R i j k μ ν).coeff r).support,
            (((R i j k μ ν).coeff r).coeff h).natAbs ≤
          c ^ (c * (1 + m + S + T * (a + b))) * (1 + m + S + T + a + b) ^ (c * (1 + m + S))) ∧
        (∀ i j k μ ν r, ((R i j k μ ν).coeff r).natDegree ≤ M + c * (1 + m + S + T * a)) ∧
        ∀ q : Fin S → Fin T → Fin T → Fin M → Fin Q.natDegree → ℤ,
          Λ * iteratedDeriv m (fun z : ℂ => ∑ i : Fin S, ∑ j : Fin T, ∑ k : Fin T,
              (∑ μ : Fin M, ∑ ν : Fin Q.natDegree,
                ((q i j k μ ν : ℤ) : ℂ) * ω ^ (μ : ℕ) * ω₁ ^ (ν : ℕ)) * z ^ (i : ℕ) *
                Complex.exp ((((j : ℕ) : ℂ) * x₁ + ((k : ℕ) : ℂ) * x₂) * z))
            ((a : ℂ) * y₁ + (b : ℂ) * y₂) =
          Polynomial.eval₂ (Polynomial.eval₂RingHom (Int.castRingHom ℂ) ω) ω₁
            (∑ i : Fin S, ∑ j : Fin T, ∑ k : Fin T, ∑ μ : Fin M, ∑ ν : Fin Q.natDegree,
              Polynomial.C (Polynomial.C (q i j k μ ν)) * R i j k μ ν)) :
    ∃ κ₁ : ℝ, 0 < κ₁ ∧ ∃ N₀ : ℕ, ∀ N : ℕ, N₀ < N →
      ∃ M : ℕ, 0 < M ∧ (M : ℝ) ≤ κ₁ * ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊ ∧ ∃ R : ℕ, 2 * R ≤ ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊ * (2 * N) * (2 * N) * M * Q.natDegree ∧
      ∃ B : Fin R → Fin ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊ → Fin (2 * N) → Fin (2 * N) → Fin M → Fin Q.natDegree → ℤ,
        (∀ e i j k' μ ν, |((B e i j k' μ ν : ℤ) : ℝ)| ≤ Real.exp (κ₁ * ((N : ℝ) ^ 2 * Real.sqrt (Real.log (N : ℝ))))) ∧
        ∀ q : Fin ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊ → Fin (2 * N) → Fin (2 * N) → Fin M → Fin Q.natDegree → ℤ,
          (∀ e, ∑ i : Fin ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊, ∑ j : Fin (2 * N), ∑ k' : Fin (2 * N), ∑ μ : Fin M, ∑ ν : Fin Q.natDegree, B e i j k' μ ν * q i j k' μ ν = 0) →
          ∀ a b m : ℕ, a < ⌊(N : ℝ) / Real.sqrt (Real.log (N : ℝ))⌋₊ → b < ⌊(N : ℝ) * Real.sqrt (Real.log (N : ℝ))⌋₊ → m < ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊ →
            iteratedDeriv m (fun z : ℂ => ∑ i : Fin ⌊(N : ℝ) ^ 2 / Real.sqrt (Real.log (N : ℝ))⌋₊, ∑ j : Fin (2 * N), ∑ k' : Fin (2 * N),
              (fun i j k' => ∑ μ : Fin M, ∑ ν : Fin Q.natDegree, ((q i j k' μ ν : ℤ) : ℂ) * ω ^ (μ : ℕ) * ω₁ ^ (ν : ℕ)) i j k' * z ^ (i : ℕ) * Complex.exp ((((j : ℕ) : ℂ) * x₁ + ((k' : ℕ) : ℂ) * x₂) * z)) ((a : ℂ) * y₁ + (b : ℂ) * y₂) = 0 := by
  sorry

end FourExp
Source
The equation count in the proof of Lemme 4 of M. Waldschmidt, Solution du huitième problème de Schneider, J. Number Theory 5 (1973), 191–202 (pp. 197–198). Formal proof: Diaz modulus mission, 30 September 2026 (C. Perassi).

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