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Existence and uniqueness of the fundamental solution Ψ′=J0SΨ\Psi' = J_0 S \PsiΨ′=J0​SΨ

Proved
AsymptoticOperator.fundamentalSolution_existsUnique

by Mazecto · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

asymptotic-operatorconley-zehnder-indexspectral-theorysymplectic-geometryunbounded-operator

Let S:S1→R2n×2nS:S^1\to\mathbb{R}^{2n\times2n}S:S1→R2n×2n be continuous. There is exactly one map Ψ:R→R2n×2n\Psi:\mathbb{R}\to\mathbb{R}^{2n\times2n}Ψ:R→R2n×2n with Ψ(0)=Id\Psi(0)=\mathrm{Id}Ψ(0)=Id that is differentiable everywhere with

Ψ′(t)=J0 S(t) Ψ(t)(t∈R),\Psi'(t)=J_0\,S(t)\,\Psi(t)\qquad(t\in\mathbb{R}),Ψ′(t)=J0​S(t)Ψ(t)(t∈R),

where SSS is viewed as a 111-periodic function on R\mathbb{R}R.

Preamble
import Definitions.Def_AsymptoticOperator_Setting
Formal statement
namespace AsymptoticOperator

open ConleyZehnder

/-- Every continuous loop `S` has exactly one fundamental solution `Ψ`:
`Ψ(0) = Id`, `Ψ' = J₀ S Ψ` on `ℝ`. -/
theorem fundamentalSolution_existsUnique {n : ℕ} (S : C(UnitAddCircle, Mat n)) :
    ∃! Ψ : ℝ → Mat n, IsFundamentalSolution S Ψ := by sorry

end AsymptoticOperator
Source
Wendl, Lectures on Symplectic Field Theory, arXiv:1612.01009, https://arxiv.org/abs/1612.01009, §3.4, p. 61 (informal there)
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. Let n≥0n \ge 0n≥0 be a natural number (the case n=0n = 0n=0 is included; then all matrices below are 0×00 \times 00×0). Write Matn\mathrm{Mat}_nMatn​ for the real 2n×2n2n \times 2n2n×2n matrices, with rows and columns indexed by two disjoint copies of {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1} (a "first block" and a "second block"). Let

J0=(0−InIn0)∈Matn.J_0 = \begin{pmatrix} 0 & -I_n \\ I_n & 0 \end{pmatrix} \in \mathrm{Mat}_n .J0​=(0In​​−In​0​)∈Matn​.

Let S1=R/ZS^1 = \mathbb{R}/\mathbb{Z}S1=R/Z and let S:S1→MatnS : S^1 \to \mathrm{Mat}_nS:S1→Matn​ be an arbitrary continuous map (continuity with respect to the entrywise topology). No further hypothesis is placed on SSS: in particular S(t)S(t)S(t) is not assumed symmetric. For t∈Rt \in \mathbb{R}t∈R, S(t)S(t)S(t) means SSS evaluated at the class t mod 1t \bmod 1tmod1, so t↦S(t)t \mapsto S(t)t↦S(t) is a 111-periodic continuous matrix function on R\mathbb{R}R.

A function Ψ:R→Matn\Psi : \mathbb{R} \to \mathrm{Mat}_nΨ:R→Matn​ (no continuity or other regularity is assumed a priori) is called a fundamental solution of SSS if

  1. Ψ(0)=I2n\Psi(0) = I_{2n}Ψ(0)=I2n​, and
  2. for every t∈Rt \in \mathbb{R}t∈R, Ψ\PsiΨ is differentiable at ttt (as a map into Matn\mathrm{Mat}_nMatn​ with its entrywise/finite-dimensional topology) with derivative
Ψ′(t)=J0 S(t) Ψ(t)\Psi'(t) = J_0\, S(t)\, \Psi(t)Ψ′(t)=J0​S(t)Ψ(t)

(matrix products, in this order).

Statement. For every nnn and every continuous loop S:R/Z→MatnS : \mathbb{R}/\mathbb{Z} \to \mathrm{Mat}_nS:R/Z→Matn​, there exists exactly one function Ψ:R→Matn\Psi : \mathbb{R} \to \mathrm{Mat}_nΨ:R→Matn​ that is a fundamental solution of SSS in the above sense: some such Ψ\PsiΨ exists, and any two such functions are equal at every t∈Rt \in \mathbb{R}t∈R.

Human review
  • Endorsed by Shuze Chen · Oct 10, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Mazecto · Oct 10, 2026

    Confirmed by the mission captain (proposal self-audit).

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