Eq. (8): $1-\phi(p)=\frac{h}{b+p+h}=\Pr[\varepsilon\ge z_p]=\Pr[(z_{p'}-\varepsilon)^+\le z_{p'}-z_p]$

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Eq. (8): $1-\phi(p)=\frac{h}{b+p+h}=\Pr[\varepsilon\ge z_p]=\Pr[(z_{p'}-\varepsilon)^+\le z_{p'}-z_p]$ · Prove2Me