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Subgroup_of_Infinite_Cyclic_Group_is_Infinite_Cyclic_Group

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

cyclic-groupsgroup-theoryproofwikisubgroups

Let G=\genaG = \gen aG=\gena be an infinite cyclic group generated by aaa, whose identity is eee. Let g∈G,g≠e:∃k∈Z,k≠0:g=akg \in G, g \ne e: \exists k \in \Z, k \ne 0: g = a^kg∈G,g=e:∃k∈Z,k=0:g=ak. Let H=\gengH = \gen gH=\geng. Then H≤GH \le GH≤G and H≅GH \cong GH≅G. Thus, all non-trivial subgroups of an infinite cyclic group are themselves infinite cyclic groups. A subgroup of G=\genaG = \gen aG=\gena is denoted as follows nG:=\genann G := \gen {a^n}nG:=\genan This notation is usually used in the context of \structZ,+\struct {\Z, +}\structZ,+, where nZn \ZnZ is (informally) understood as '''the set of integer multiples of nnn'''.

Preamble
import Mathlib.Analysis.Complex.Basic
import Mathlib.GroupTheory.SpecificGroups.Cyclic
Formal statement
theorem Subgroup_of_Infinite_Cyclic_Group_is_Infinite_Cyclic_Group {G : Type _} [Group G] [IsCyclic G] [Infinite G] (H : Subgroup G) (hH : H ≠ ⊥) : IsCyclic H := by sorry
Source
https://proofwiki.org/wiki/Subgroup_of_Infinite_Cyclic_Group_is_Infinite_Cyclic_Group

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