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In the aligned, norm-free case, u, ū and 2πi satisfy no rational quadratic relation

Proved
DiazModulus.aligned_norm_free_no_quadratic_relation

by carlok · Sep 25, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let u=x+iyu = x + iyu=x+iy with x≠0x \neq 0x=0, let r∈Qr \in \mathbb{Q}r∈Q, and put β=π(y+rπ)\beta = \pi(y + r\pi)β=π(y+rπ). Suppose that β≠0\beta \neq 0β=0, that β\betaβ and ∣u∣2|u|^{2}∣u∣2 are algebraic, and that ∣u∣2∉Qβ|u|^{2} \notin \mathbb{Q}\beta∣u∣2∈/Qβ. Then uuu, uˉ\bar uuˉ and 2πi2\pi i2πi satisfy no non-trivial rational quadratic relation: if

∑k,lFkl ekel=0,e=(u,uˉ,2πi), Fkl∈Q,\sum_{k,l} F_{kl}\, e_k e_l = 0, \qquad e = (u, \bar u, 2\pi i),\ F_{kl} \in \mathbb{Q},k,l∑​Fkl​ek​el​=0,e=(u,uˉ,2πi), Fkl​∈Q,

then Fkl+Flk=0F_{kl} + F_{lk} = 0Fkl​+Flk​=0 for all k,lk, lk,l.

These are the hypotheses of DiazModulus.aligned_norm_free_no_rational_log_matrix, without the transcendence of π\piπ, which that node assumes and which is now taken from DiazModulus.pi_transcendental. With DiazModulus.four_exp_barrier_of_no_quadratic_relation it gives that node.

Preamble
import Mathlib
Formal statement
open ComplexConjugate

namespace DiazModulus

theorem aligned_norm_free_no_quadratic_relation (u : ℂ) (r : ℚ) (hre : u.re ≠ 0)
    (hβ0 : Real.pi * (u.im + (r : ℝ) * Real.pi) ≠ 0)
    (hβ : IsAlgebraic ℚ ((Real.pi * (u.im + (r : ℝ) * Real.pi) : ℝ) : ℂ))
    (hρ : IsAlgebraic ℚ ((((‖u‖ : ℝ)) ^ 2 : ℝ) : ℂ))
    (hfree : ¬ ∃ c : ℚ, (‖u‖ : ℝ) ^ 2 = (c : ℝ) * (Real.pi * (u.im + (r : ℝ) * Real.pi)))
    (F : Fin 3 → Fin 3 → ℚ)
    (h : ∑ k, ∑ l, (F k l : ℂ) *
      (![u, conj u, 2 * ((Real.pi : ℝ) : ℂ) * Complex.I] k *
        ![u, conj u, 2 * ((Real.pi : ℝ) : ℂ) * Complex.I] l) = 0) :
    ∀ k l, F k l + F l k = 0 := by
  sorry

end DiazModulus
Source
Formal proof: Diaz modulus mission, 25 September 2026 (C. Perassi); extracted from the proof of DiazModulus.aligned_norm_free_no_rational_log_matrix.

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