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Stable circular orbits exist for n=3n=3n=3

Proved
TegmarkDimensionality.stable_orbit_three_dims

by Lucas · Oct 2, 2026 · Mathlib 0df444a (Lean v4.33.1)

classical-mechanicsmathematical-physics

Let μ>0\mu>0μ>0, k>0k>0k>0 and L≠0L\neq0L=0. The effective potential of the three-dimensional Kepler problem,

U(r)=L22μr2−kr,U(r)=\frac{L^2}{2\mu r^2}-\frac{k}{r},U(r)=2μr2L2​−rk​,

has a strict local minimum at some r0>0r_0>0r0​>0. That is, there is r0>0r_0>0r0​>0 with U(r0)<U(r)U(r_0)<U(r)U(r0​)<U(r) for all r≠r0r\neq r_0r=r0​ near r0r_0r0​.

So for n=3n=3n=3 the two-body problem has stable (circular, and nearby elliptic) orbits, unlike the case n>3n>3n>3.

Preamble
import Mathlib
open Filter Topology
Formal statement
namespace TegmarkDimensionality

/-- In `n = 3` space dimensions, with the inverse-square attraction (potential `-k/r`) and
nonzero angular momentum, the effective radial potential `U(r) = L²/(2 μ r²) - k/r` has a
strict local minimum at some radius `r₀ > 0` (a stable circular orbit). -/
theorem stable_orbit_three_dims (μ k L : ℝ) (hμ : 0 < μ) (hk : 0 < k) (hL : L ≠ 0) :
    ∃ r₀ : ℝ, 0 < r₀ ∧
      ∀ᶠ r in 𝓝[≠] r₀,
        L ^ 2 / (2 * μ * r₀ ^ 2) - k / r₀ < L ^ 2 / (2 * μ * r ^ 2) - k / r := by sorry

end TegmarkDimensionality
Source
M. Tegmark, *On the dimensionality of spacetime*, Class. Quantum Grav. 14 (1997) L69–L75, https://doi.org/10.1088/0264-9381/14/4/002, p. L70–L71 ('the familiar case, n = 3, which gives either stable elliptic orbits or non-bound parabolic and hyperbolic orbits')
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

NON-BLIND READ-BACK — NOT INDEPENDENT TESTIMONY. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement below, with full knowledge of the source paper and of the intended meaning. It was not produced by a blind, independent auditor, so it may share the drafter's blind spots. Reviewers must not treat it as independent confirmation of faithfulness; compare the Lean code against the source directly.

Let μ,k,L\mu,k,Lμ,k,L be real numbers with μ>0\mu>0μ>0, k>0k>0k>0 and L≠0L\neq0L=0. With U(r)=L22μr2−krU(r)=\dfrac{L^2}{2\mu r^2}-\dfrac{k}{r}U(r)=2μr2L2​−rk​, using Lean's convention x/0=0x/0=0x/0=0, the theorem asserts that there exists a real r0>0r_0>0r0​>0 such that U(r0)<U(r)U(r_0)<U(r)U(r0​)<U(r) for every r≠r0r\neq r_0r=r0​ in some neighbourhood of r0r_0r0​. In other words, UUU has a strict local minimum at some positive point.

Human review
  • Endorsed by Shuze Chen · Oct 2, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 2, 2026

    Confirmed by the mission captain (proposal self-audit).

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