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Kernel and cokernel of Cauchy–Riemann operators with a large antilinear zeroth-order term

Proved
CauchyRiemannIndex.large_antilinear_perturbation_index

by Mazecto · Oct 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

cauchy-riemannconley-zehnder-indexfredholm-indexsobolev-spacessymplectic-geometry

Let n=1n=1n=1, let S±S^\pmS± be continuous loops of symmetric 2×22\times22×2 matrices with nondegenerate asymptotic operators, and let S:R×S1→R2×2S:\mathbb{R}\times S^1\to\mathbb{R}^{2\times2}S:R×S1→R2×2 be continuous with S(s,⋅)→S±S(s,\cdot)\to S^\pmS(s,⋅)→S± uniformly as s→±∞s\to\pm\inftys→±∞. Let β:R×S1→C\beta:\mathbb{R}\times S^1\to\mathbb{C}β:R×S1→C be smooth with bounded first derivative, such that ∣β∣|\beta|∣β∣ and 1/∣β∣1/|\beta|1/∣β∣ are bounded for large ∣s∣|s|∣s∣, and such that its zeros form finite sets Z+Z^+Z+ (positive zeros) and Z−Z^-Z− (negative zeros) with the following normal form: for some r>0r>0r>0 and every ζ∈Z±\zeta\in Z^\pmζ∈Z±, on the disc ∣z∣<r|z|<r∣z∣<r around ζ\zetaζ one has S=0S=0S=0 and

β(ζ+z)=z  (ζ∈Z+),β(ζ+z)=zˉ  (ζ∈Z−).\beta(\zeta+z)=z\ \ (\zeta\in Z^+),\qquad\beta(\zeta+z)=\bar z\ \ (\zeta\in Z^-).β(ζ+z)=z  (ζ∈Z+),β(ζ+z)=zˉ  (ζ∈Z−).

For σ>0\sigma>0σ>0 let Dση=∂sη+J0∂tη+Sη+σβηˉD_\sigma\eta=\partial_s\eta+J_0\partial_t\eta+S\eta+\sigma\beta\bar\etaDσ​η=∂s​η+J0​∂t​η+Sη+σβηˉ​, acting from W1,2W^{1,2}W1,2 to L2L^2L2. Then:

  1. if Z−=∅Z^-=\emptysetZ−=∅, then for all sufficiently large σ\sigmaσ, DσD_\sigmaDσ​ is surjective and dim⁡ker⁡Dσ=#Z+\dim\ker D_\sigma=\#Z^+dimkerDσ​=#Z+;
  2. if Z+=∅Z^+=\emptysetZ+=∅, then for all sufficiently large σ\sigmaσ, DσD_\sigmaDσ​ is injective and dim⁡coker⁡Dσ=#Z−\dim\operatorname{coker}D_\sigma=\#Z^-dimcokerDσ​=#Z−.

In either case ind⁡Dσ=#Z+−#Z−\operatorname{ind}D_\sigma=\#Z^+-\#Z^-indDσ​=#Z+−#Z− for all sufficiently large σ\sigmaσ.

Formalization Note C=R2\mathbb{C}=\mathbb{R}^2C=R2 via (x,y)↦x+iy(x,y)\mapsto x+iy(x,y)↦x+iy, and η↦βηˉ\eta\mapsto\beta\bar\etaη↦βηˉ​ is the matrix antilinearMat β, so DσD_\sigmaDσ​ is DSσD_{S_\sigma}DSσ​​ with Sσ=S+σ⋅S_\sigma=S+\sigma\cdotSσ​=S+σ⋅antilinearMat ∘ β. Points of the cylinder are pairs (s,t)(s,t)(s,t) and ζ+z\zeta+zζ+z means (ζs+Re⁡z,ζt+Im⁡z)(\zeta_s+\operatorname{Re}z,\zeta_t+\operatorname{Im}z)(ζs​+Rez,ζt​+Imz); β\betaβ is 111-periodic in ttt, the zeros are listed in R×[0,1)\mathbb{R}\times[0,1)R×[0,1), and every zero of β\betaβ is a ttt-translate by an integer of a listed one. Wendl's § 5.5 asks, near each zero, for a holomorphic chart onto the unit disc in which dvold\mathrm{vol}dvol is standard, the operator is ∂ˉ\bar\partial∂ˉ and β\betaβ is zzz or zˉ\bar zzˉ; here the chart is a translation of the coordinates (s,t)(s,t)(s,t), the trivialization is the global one, and the area form is ds dtds\,dtdsdt. Replacing the unit disc by a disc of radius rrr rescales β\betaβ in the chart by r2r^2r2, which only reparametrizes σ\sigmaσ, and kernels and cokernels do not depend on the area form. The exponent is p=2p=2p=2 (Wendl, Assumption 5.7). The conclusions are stated with crRange 2 … = ⊤, crKernel 2 … = ⊥ and finrank of crKernel 2 … and of LpCyl 1 2 ⧸ crRange 2 …, together with their finite-dimensionality.

Preamble
import Definitions.Def_CauchyRiemannIndex_Setting
import Mathlib.Analysis.Calculus.ContDiff.Basic
Formal statement
namespace CauchyRiemannIndex

open MeasureTheory Matrix Filter Topology
open scoped ENNReal NNReal ContDiff RealInnerProductSpace

/-- Wendl, Proposition 5.27 (p. 102), with the assumptions of § 5.5 (p. 94), on the cylinder with the
trivial line bundle and `p = 2`: let `D_S` (`n = 1`) be asymptotic to nondegenerate loops `S±` of
symmetric matrices, and let `β : ℝ × S¹ → ℂ` be smooth with bounded derivative, with `|β|` and `1/|β|`
bounded for large `|s|`, whose zeros (mod `t ↦ t + 1`) are the finite sets `Z⁺` (positive zeros) and
`Z⁻` (negative zeros), such that on a disc of radius `r` around each zero `ζ` the operator is `∂̄`
(`S = 0`) and `β(ζ + z) = z` for `ζ ∈ Z⁺`, `β(ζ + z) = z̄` for `ζ ∈ Z⁻`. Put
`D_σ η = D_S η + σ β η̄`. If `Z⁻ = ∅`, then for all large `σ`, `D_σ : W^{1,2} → L²` is surjective with
`dim ker D_σ = #Z⁺`; if `Z⁺ = ∅`, then for all large `σ`, `D_σ` is injective with
`dim coker D_σ = #Z⁻`. -/
theorem large_antilinear_perturbation_index (Splus Sminus : ℝ → Mat 1) (hSplus : IsSymLoop Splus)
    (hSminus : IsSymLoop Sminus) (hplus : IsNondegenerate Splus) (hminus : IsNondegenerate Sminus)
    (S : ℝ × ℝ → Mat 1) (hS : IsAsymptoticTo S Splus Sminus)
    (β : ℝ × ℝ → ℂ) (hβ : ContDiff ℝ ∞ β) (hβper : ∀ s t, β (s, t + 1) = β (s, t))
    (hβC1 : ∃ C : ℝ, ∀ x, ‖fderiv ℝ β x‖ ≤ C)
    (hβends : ∃ (R c : ℝ), 0 < c ∧ ∀ s t, R ≤ |s| → c ≤ ‖β (s, t)‖ ∧ ‖β (s, t)‖ ≤ 1 / c)
    (Zplus Zminus : Finset (ℝ × ℝ)) (hZ : ∀ ζ ∈ Zplus ∪ Zminus, 0 ≤ ζ.2 ∧ ζ.2 < 1)
    (hdisj : Disjoint Zplus Zminus)
    (hzero : ∀ x : ℝ × ℝ, β x = 0 ↔ ∃ ζ ∈ Zplus ∪ Zminus, ∃ m : ℤ, x = (ζ.1, ζ.2 + m))
    (r : ℝ) (hr : 0 < r)
    (hplusZ : ∀ ζ ∈ Zplus, ∀ z : ℂ, ‖z‖ < r →
      β (ζ.1 + z.re, ζ.2 + z.im) = z ∧ S (ζ.1 + z.re, ζ.2 + z.im) = 0)
    (hminusZ : ∀ ζ ∈ Zminus, ∀ z : ℂ, ‖z‖ < r →
      β (ζ.1 + z.re, ζ.2 + z.im) = (starRingEnd ℂ) z ∧ S (ζ.1 + z.re, ζ.2 + z.im) = 0) :
    (Zminus = ∅ → ∃ σ₀ : ℝ, ∀ σ ≥ σ₀,
      crRange 2 (fun x => S x + σ • antilinearMat (β x)) = ⊤ ∧
      FiniteDimensional ℝ (crKernel 2 (fun x => S x + σ • antilinearMat (β x))) ∧
      Module.finrank ℝ (crKernel 2 (fun x => S x + σ • antilinearMat (β x))) = Zplus.card) ∧
    (Zplus = ∅ → ∃ σ₀ : ℝ, ∀ σ ≥ σ₀,
      crKernel 2 (fun x => S x + σ • antilinearMat (β x)) = ⊥ ∧
      FiniteDimensional ℝ (LpCyl 1 2 ⧸ crRange 2 (fun x => S x + σ • antilinearMat (β x))) ∧
      Module.finrank ℝ (LpCyl 1 2 ⧸ crRange 2 (fun x => S x + σ • antilinearMat (β x))) =
        Zminus.card) := by
  sorry

end CauchyRiemannIndex
Source
C. Wendl, Lectures on Symplectic Field Theory, arXiv:1612.01009, https://arxiv.org/abs/1612.01009, Lecture 5, Proposition 5.27, p. 102, with the assumptions of § 5.5, p. 94 (cylinder, trivial line bundle, p = 2)
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What the Lean code literally says, in plain math · claude-opus-5-5

Read-back: CauchyRiemannIndex.large_antilinear_perturbation_index

Setting. n=1n=1n=1, p=2p=2p=2; loops S±:R→R2×2S^\pm:\mathbb R\to\mathbb R^{2\times2}S±:R→R2×2; S:R×R→R2×2S:\mathbb R\times\mathbb R\to\mathbb R^{2\times2}S:R×R→R2×2; β:R×R→C\beta:\mathbb R\times\mathbb R\to\mathbb Cβ:R×R→C; finite sets Z+,Z−⊂R×RZ^+,Z^-\subset\mathbb R\times\mathbb RZ+,Z−⊂R×R; r∈Rr\in\mathbb Rr∈R.

Hypotheses. S±S^\pmS± continuous 1-periodic symmetric loops, nondegenerate; SSS continuous, ttt-periodic, asymptotic to S±S^\pmS± (entrywise, uniformly in ttt). β\betaβ is C∞C^\inftyC∞, 1-periodic in ttt, sup⁡x∥dβ(x)∥<∞\sup_x\|d\beta(x)\|<\inftysupx​∥dβ(x)∥<∞, and ∃R, c>0\exists R,\,c>0∃R,c>0 with c≤∣β(s,t)∣≤1/cc\le|\beta(s,t)|\le 1/cc≤∣β(s,t)∣≤1/c for ∣s∣≥R|s|\ge R∣s∣≥R. Every ζ∈Z+∪Z−\zeta\in Z^+\cup Z^-ζ∈Z+∪Z− has ζ2∈[0,1)\zeta_2\in[0,1)ζ2​∈[0,1); Z+∩Z−=∅Z^+\cap Z^-=\emptysetZ+∩Z−=∅; β(x)=0  ⟺  x=(ζ1,ζ2+m)\beta(x)=0\iff x=(\zeta_1,\zeta_2+m)β(x)=0⟺x=(ζ1​,ζ2​+m) for some ζ∈Z+∪Z−\zeta\in Z^+\cup Z^-ζ∈Z+∪Z−, m∈Zm\in\mathbb Zm∈Z. For some r>0r>0r>0 and all ∣z∣<r|z|<r∣z∣<r (writing z=a+ib↦(ζ1+a,ζ2+b)z=a+ib\mapsto(\zeta_1+a,\zeta_2+b)z=a+ib↦(ζ1​+a,ζ2​+b)): β(ζ+z)=z\beta(\zeta+z)=zβ(ζ+z)=z, S(ζ+z)=0S(\zeta+z)=0S(ζ+z)=0 for ζ∈Z+\zeta\in Z^+ζ∈Z+; β(ζ+z)=zˉ\beta(\zeta+z)=\bar zβ(ζ+z)=zˉ, S(ζ+z)=0S(\zeta+z)=0S(ζ+z)=0 for ζ∈Z−\zeta\in Z^-ζ∈Z−.

Definitions used. crKernel, crRange (real spans of ker⁡\kerker / image of D=∂s+J0∂t+(⋅)D=\partial_s+J_0\partial_t+(\cdot)D=∂s​+J0​∂t​+(⋅) on W1,2→L2W^{1,2}\to L^2W1,2→L2 of R×S1\mathbb R\times S^1R×S1), antilinearMat β=(Re⁡βIm⁡βIm⁡β−Re⁡β)\beta=\begin{pmatrix}\operatorname{Re}\beta&\operatorname{Im}\beta\\\operatorname{Im}\beta&-\operatorname{Re}\beta\end{pmatrix}β=(ReβImβ​Imβ−Reβ​). Check: for z=x+iyz=x+iyz=x+iy, βzˉ=(ax+by)+i(bx−ay)\beta\bar z=(ax+by)+i(bx-ay)βzˉ=(ax+by)+i(bx−ay) (β=a+ib\beta=a+ibβ=a+ib), which is exactly that matrix applied to (x,y)(x,y)(x,y); J0=J_0=J0​= Matrix.J =(0−110)=\begin{pmatrix}0&-1\\1&0\end{pmatrix}=(01​−10​) is multiplication by iii. So with Dσ:=D_\sigma:=Dσ​:= coefficient S+σ S+\sigma\,S+σantilinearMat(β)(\beta)(β),

Dση=∂sη+i∂tη+Sη+σβηˉ=2∂ˉη+Sη+σβηˉ(w=s+it).D_\sigma\eta=\partial_s\eta+i\partial_t\eta+S\eta+\sigma\beta\bar\eta=2\bar\partial\eta+S\eta+\sigma\beta\bar\eta\quad(w=s+it).Dσ​η=∂s​η+i∂t​η+Sη+σβηˉ​=2∂ˉη+Sη+σβηˉ​(w=s+it).

Conclusion. (i) If Z−=∅Z^-=\emptysetZ−=∅: ∃σ0 ∀σ≥σ0\exists\sigma_0\ \forall\sigma\ge\sigma_0∃σ0​ ∀σ≥σ0​, DσD_\sigmaDσ​ is onto L2L^2L2, ker⁡Dσ\ker D_\sigmakerDσ​ is finite-dimensional and dim⁡Rker⁡Dσ=#Z+\dim_{\mathbb R}\ker D_\sigma=\#Z^+dimR​kerDσ​=#Z+. (ii) If Z+=∅Z^+=\emptysetZ+=∅: ∃σ0 ∀σ≥σ0\exists\sigma_0\ \forall\sigma\ge\sigma_0∃σ0​ ∀σ≥σ0​, ker⁡Dσ=0\ker D_\sigma=0kerDσ​=0, coker⁡Dσ\operatorname{coker}D_\sigmacokerDσ​ is finite-dimensional and dim⁡Rcoker⁡Dσ=#Z−\dim_{\mathbb R}\operatorname{coker}D_\sigma=\#Z^-dimR​cokerDσ​=#Z−.

Degenerate cases. Z+=Z−=∅Z^+=Z^-=\emptysetZ+=Z−=∅ (e.g. R≤0R\le 0R≤0, so ∣β∣≥c|\beta|\ge c∣β∣≥c everywhere): both parts apply, DσD_\sigmaDσ​ invertible for large σ\sigmaσ; true by the coercive estimate ∥Dση∥≥(σc−O(σ)−∥S∥∞)∥η∥\|D_\sigma\eta\|\ge(\sigma c-O(\sqrt\sigma)-\|S\|_\infty)\|\eta\|∥Dσ​η∥≥(σc−O(σ​)−∥S∥∞​)∥η∥ (cross term 2σ⟨2∂ˉη,βηˉ⟩2\sigma\langle 2\bar\partial\eta,\beta\bar\eta\rangle2σ⟨2∂ˉη,βηˉ​⟩ integrates by parts to O(σ∥dβ∥∞)∥η∥2O(\sigma\|d\beta\|_\infty)\|\eta\|^2O(σ∥dβ∥∞​)∥η∥2).

Remarks.

  • Local model check. Near ζ∈Z+\zeta\in Z^+ζ∈Z+ (S=0S=0S=0, β=z\beta=zβ=z): 2∂ˉη+σzηˉ=02\bar\partial\eta+\sigma z\bar\eta=02∂ˉη+σzηˉ​=0; η=e−σ∣z∣2/2\eta=e^{-\sigma|z|^2/2}η=e−σ∣z∣2/2 gives 2∂ˉη=−σzη2\bar\partial\eta=-\sigma z\eta2∂ˉη=−σzη, so it solves the equation exactly for real η\etaη-values (ie−σ∣z∣2/2i e^{-\sigma|z|^2/2}ie−σ∣z∣2/2 does not): one real Gaussian per positive zero, matching real finrank =#Z+=\#Z^+=#Z+. Near ζ∈Z−\zeta\in Z^-ζ∈Z− (β=zˉ\beta=\bar zβ=zˉ): the L2L^2L2-real adjoint of η↦βηˉ\eta\mapsto\beta\bar\etaη↦βηˉ​ is itself and of 2∂ˉ2\bar\partial2∂ˉ is −2∂-2\partial−2∂; −2∂ξ+σzˉξˉ=0-2\partial\xi+\sigma\bar z\bar\xi=0−2∂ξ+σzˉξˉ​=0 is solved by ξ=i e−σ∣z∣2/2\xi=i\,e^{-\sigma|z|^2/2}ξ=ie−σ∣z∣2/2: one real cokernel Gaussian per negative zero. Orientation: z=(s−ζ1)+i(t−ζ2)z=(s-\zeta_1)+i(t-\zeta_2)z=(s−ζ1​)+i(t−ζ2​) is the coordinate in which ∂s+J0∂t=2∂ˉ\partial_s+J_0\partial_t=2\bar\partial∂s​+J0​∂t​=2∂ˉ, so "β=z\beta=zβ=z" is a positive (degree +1+1+1) zero. Signs and real dimensions consistent.
  • Consistency with the index: signed zero count #Z+−#Z−=wind β(+∞,⋅)−wind β(−∞,⋅)\#Z^+-\#Z^-=\mathrm{wind}\,\beta(+\infty,\cdot)-\mathrm{wind}\,\beta(-\infty,\cdot)#Z+−#Z−=windβ(+∞,⋅)−windβ(−∞,⋅) (boundary of [a,b]×S1[a,b]\times S^1[a,b]×S1 for ds∧dtds\wedge dtds∧dt is {b}×S1−{a}×S1\{b\}\times S^1-\{a\}\times S^1{b}×S1−{a}×S1, ttt increasing), matching index_eq_winding_of_antilinear_deformation.
  • The Lean hypotheses do not require β\betaβ to converge as s→±∞s\to\pm\inftys→±∞ (only c≤∣β∣≤1/cc\le|\beta|\le1/cc≤∣β∣≤1/c and ∥dβ∥\|d\beta\|∥dβ∥ bounded there). This is weaker than an "asymptotic to β±\beta^\pmβ±" assumption, but the conclusion still follows from the coercive estimate above, which uses exactly these bounds (plus boundedness of SSS, implied by IsAsymptoticTo). No Fredholm assumption on DσD_\sigmaDσ​ is needed since the conclusion states finite-dimensionality explicitly.
  • Normal form vs periodicity. If r>1/2r>1/2r>1/2 then z=iaz=iaz=ia and z=i(a−1)z=i(a-1)z=i(a−1) with 1−r<a<r1-r<a<r1−r<a<r both lie in the disc and give β(ζ1,ζ2+a)=ia≠i(a−1)=β(ζ1,ζ2+a−1)\beta(\zeta_1,\zeta_2+a)=ia\ne i(a-1)=\beta(\zeta_1,\zeta_2+a-1)β(ζ1​,ζ2​+a)=ia=i(a−1)=β(ζ1​,ζ2​+a−1), contradicting ttt-periodicity; so the hypotheses force r≤1/2r\le1/2r≤1/2. Two discs (around ζ≠ζ′\zeta\ne\zeta'ζ=ζ′, or around ζ\zetaζ and an integer translate) cannot meet: at a common point www, w−ζ=β(w)=w−ζ′w-\zeta=\beta(w)=w-\zeta'w−ζ=β(w)=w−ζ′ (or w−ζ‾=w−ζ′‾\overline{w-\zeta}=\overline{w-\zeta'}w−ζ​=w−ζ′​ for two negative zeros, again forcing ζ=ζ′\zeta=\zeta'ζ=ζ′). For one positive and one negative zero a single common point is possible, but the overlap of two open discs is open, and on it β\betaβ would be both w↦w−ζw\mapsto w-\zetaw↦w−ζ and w↦w−ζ′‾w\mapsto\overline{w-\zeta'}w↦w−ζ′​, i.e. ∂β=1\partial\beta=1∂β=1 and ∂β=0\partial\beta=0∂β=0 at once, impossible. Hence the hypotheses force the discs to be pairwise disjoint mod 1. These are consequences, not contradictions: rrr is a hypothesis parameter, and a small rrr is always available for a genuine example.

Soundness checks.

  1. Junk/coercions: finrank used only alongside an explicit FiniteDimensional, so no junk 0; Zplus.card is ℕ, compared in ℕ. σ • antilinearMat (β x) is real scalar on Mat 1; S x + … pointwise. starRingEnd ℂ z is zˉ\bar zzˉ. ‖fderiv ℝ β x‖ is the operator norm. Quantifier order: ∃σ0 ∀σ≥σ0\exists\sigma_0\,\forall\sigma\ge\sigma_0∃σ0​∀σ≥σ0​ inside each implication, after all data are fixed; correct. Binder scope of ∀ z, ‖z‖ < r → β … ∧ S … = 0 covers both conjuncts as intended. hZ normalizes representatives to t∈[0,1)t\in[0,1)t∈[0,1), so card counts zeros mod 1 without duplicates.
  2. Satisfiable, not vacuous: Z+={(s0,0)}Z^+=\{(s_0,0)\}Z+={(s0​,0)}, Z−=∅Z^-=\emptysetZ−=∅: take β0(s,t)=(a(s)e2πit−(1−a(s)))/π\beta_0(s,t)=\big(a(s)e^{2\pi it}-(1-a(s))\big)/\piβ0​(s,t)=(a(s)e2πit−(1−a(s)))/π with smooth monotone aaa, a→0a\to0a→0 at −∞-\infty−∞, a→1a\to1a→1 at +∞+\infty+∞, a(s0)=1/2a(s_0)=1/2a(s0​)=1/2, a′(s0)=π/2a'(s_0)=\pi/2a′(s0​)=π/2: its only zeros are (s0,m)(s_0,m)(s0​,m) and its Jacobian there is the identity, so β0(ζ+z)=z+O(∣z∣2)\beta_0(\zeta+z)=z+O(|z|^2)β0​(ζ+z)=z+O(∣z∣2). Put β=χz+(1−χ)β0\beta=\chi z+(1-\chi)\beta_0β=χz+(1−χ)β0​ with a cutoff χ(∣z∣)\chi(|z|)χ(∣z∣) equal to 1 on ∣z∣<r|z|<r∣z∣<r and 0 on ∣z∣>2r|z|>2r∣z∣>2r (extended periodically): for small rrr the two terms differ by O(∣z∣2)≪∣z∣O(|z|^2)\ll|z|O(∣z∣2)≪∣z∣ on the annulus, so no new zeros, and β(ζ+z)=z\beta(\zeta+z)=zβ(ζ+z)=z exactly on the disc; ∣β∣→1|\beta|\to1∣β∣→1 at both ends, dβd\betadβ bounded, smooth, periodic. Take S=χends(s)⋅S±S=\chi_{\text{ends}}(s)\cdot S^\pmS=χends​(s)⋅S± with S±=±εIS^\pm=\pm\varepsilon IS±=±εI (0<ε<π0<\varepsilon<\pi0<ε<π, nondegenerate) and χends=0\chi_{\text{ends}}=0χends​=0 on ∣s∣≤∣s0∣+1|s|\le|s_0|+1∣s∣≤∣s0​∣+1, so S=0S=0S=0 on the disc. All hypotheses hold; conclusion (i) predicts a one-dimensional real kernel (the Gaussian) and surjectivity: consistent with index =1=wind(+)−wind(−)=1=\mathrm{wind}(+)-\mathrm{wind}(-)=1=wind(+)−wind(−). (Here DSD_SDS​ itself has index μ(εI)−μ(−εI)=2\mu(\varepsilon I)-\mu(-\varepsilon I)=2μ(εI)−μ(−εI)=2; no contradiction, since σβηˉ\sigma\beta\bar\etaσβηˉ​ does not decay at the ends, so DσD_\sigmaDσ​ has different asymptotic operators than DSD_SDS​.) True (Wendl Prop. 5.27, under hypotheses at least as strong as needed for its proof).

Verdict: no mis-formalization observed

Human review
  • Endorsed by Shuze Chen · Oct 14, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Mazecto · Oct 14, 2026

    Confirmed by the mission captain (proposal self-audit).

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