lean_workbook_plus_29581

Disproved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Prove that $a^2+b^2+c^2+\frac{abc(a+b+c)^2}{a^2b+b^2c+c^2a}\ge 2(ab+bc+ca)$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_29581 : ∀ a b c : ℝ, a^2 + b^2 + c^2 + (a * b * c * (a + b + c)^2) / (a^2 * b + b^2 * c + c^2 * a) ≥ 2 * (a * b + b * c + c * a)   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook

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