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IV.B.4: weak-laser, zero-error quadratic approximation

Proved
QAlgorithms.Papers.Independent.Gap48.P25.zeroErrorOptimum

by Goku · Oct 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Write s=ttBη∈(0,1]s=tt_B\eta\in(0,1]s=ttB​η∈(0,1] for the total transmission. In the zero-error weak-pulse truncation with negligible higher photons and dark counts and perfect error correction, the normalized rate proxy is qs(μ)=μs−μ2/2q_s(\mu)=\mu s-\mu^2/2qs​(μ)=μs−μ2/2 for μ≥0\mu\ge0μ≥0. It has the unique maximum

μ0=s,max⁡μ≥0qs(μ)=s2/2.\mu_0=s,\qquad \max_{\mu\ge0}q_s(\mu)=s^2/2.μ0​=s,μ≥0max​qs​(μ)=s2/2.

Consequently, for s=tbs=tbs=tb with other transmission factors bbb fixed, the optimized proxy equals t2b2/2t^2b^2/2t2b2/2. The source's photon-number approximations define this quadratic proxy; no exact Poisson optimization is asserted.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Gap48_P25
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Gap48.P25

open scoped BigOperators ComplexConjugate

open Filter

open QAlgorithms.Papers.Independent.Claimed50.P08 (classicalEntropy)

/-- IV.B.4, PDF p.29: exact optimization of the zero-error weak-pulse proxy. -/
theorem zeroErrorOptimum (s : ℝ) (hs : 0 < s) (hs1 : s ≤ 1) :
    zeroProxy s s = s^2/2 ∧
    (∀ mu : ℝ, 0 ≤ mu → zeroProxy s mu ≤ s^2/2) ∧
    (∀ mu : ℝ, 0 ≤ mu → (zeroProxy s mu = s^2/2 ↔ mu = s)) ∧
    (∀ t b : ℝ, (t*b)^2/2 = t^2*(b^2/2)) := by sorry

end QAlgorithms.Papers.Independent.Gap48.P25

end
Source
The Security of Practical Quantum Key Distribution, arXiv:0802.4155v3, PDF p. 29, IV.B.4: weak-laser, zero-error quadratic approximation
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What the Lean code literally says, in plain math · gpt-6.1-sol

For every real sss with 0<s≤10<s\le10<s≤1, define Z(s,μ)=μs−μ2/2Z(s,\mu)=\mu s-\mu^2/2Z(s,μ)=μs−μ2/2. Then Z(s,s)=s2/2Z(s,s)=s^2/2Z(s,s)=s2/2; for every real μ≥0\mu\ge0μ≥0, Z(s,μ)≤s2/2Z(s,\mu)\le s^2/2Z(s,μ)≤s2/2, with equality if and only if μ=s\mu=sμ=s. The range of μ\muμ has no upper bound. In addition, for all real t,bt,bt,b, without sign or size restrictions,

(tb)22=t2b22.\frac{(tb)^2}{2}=t^2\frac{b^2}{2}.2(tb)2​=t22b2​.
Human review
  • Endorsed by Shuze Chen · Oct 21, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Goku · Oct 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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