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Finite powerset Bernoulli-family moment identity

Proved
FinitePowersetBernoulliFamilyMoment

by xuanji · Sep 26, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricscrossing-numberprobability

Let SSS be a finite set, let III be a finite index set, and let each index iii have a support set contained in SSS. For a real parameter ppp, the weighted sum over all subsets X⊆SX\subseteq SX⊆S of the number of supports contained in XXX equals the sum of the individual support weights:

∑X⊆Sp∣X∣(1−p)∣S∖X∣ ∣{i∈I:support⁡(i)⊆X}∣=∑i∈Ip∣support⁡(i)∣.\sum_{X\subseteq S}p^{|X|}(1-p)^{|S\setminus X|} \,\bigl|\{i\in I:\operatorname{support}(i)\subseteq X\}\bigr| = \sum_{i\in I}p^{|\operatorname{support}(i)|}.X⊆S∑​p∣X∣(1−p)∣S∖X∣​{i∈I:support(i)⊆X}​=i∈I∑​p∣support(i)∣.

This moment identity is the probabilistic averaging step in the crossing-lemma argument, applied respectively to vertices, edges, and crossing points.

Preamble
import Mathlib.Analysis.InnerProductSpace.PiL2
import Mathlib.Algebra.BigOperators.Ring.Finset

open Classical
noncomputable section
Formal statement
lemma FinitePowersetBernoulliFamilyMoment {α ι : Type*}
    (S : Finset α) (I : Finset ι) (support : ι → Finset α)
    (hsupport : ∀ i ∈ I, support i ⊆ S) (p : ℝ) :
    ∑ X ∈ S.powerset,
        p ^ X.card * (1 - p) ^ (S \ X).card *
          ((I.filter fun i => support i ⊆ X).card : ℝ) =
      ∑ i ∈ I, p ^ (support i).card := by sorry
Source
https://github.com/wpegden/crossing-consequences/blob/8769d142033fce042f502bf2857afb6b1375b5c3/Tablet/FinitePowersetBernoulliFamilyMoment.lean#L1-L91

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